Question

我正在使用ajax / jquery在表单上进行数据库保存/抓取。我有节省和抓住的问题。我的ajax一直在失败，我不知道为什么。我知道这应该有效。我将ajaxCall移动到它自己的函数，在加载和提交时调用它，这就是事情似乎向南的时候。有人能指出我在错误的方向上正确的方向。我在下面有我的jquery和php。

JQUERY / AJAX代码

$（document）.ready（function（）{ AjaxCall的（）;

$('#submitBtn').on('click',function(event) {
    var formData = $('form').serialize();
    event.preventDefault();
    ajaxCall(formData);
}); //END OF .ON

function ajaxCall(formData) {
    $.ajax({
        url: "php/save.php",
        type: "POST",
        dataType: "json",
        //dataType: "string",
        data: formData,
        async: true,
        success: successCall,
        error: errorCall
    });
} //END OF AJAX CALL FUNCTION

function errorCall() {
    alert("There was an error with this request!")
}// END OF ERROR CALL FUNCTION

function successCall(data) {
    //var records = $.parseJSON();
    var record = "";
    console.log(data);

    /*$.each(data, function() {
        ID = this['ID'];
        NAME = this['NAME'];
        PHONE = this['PHONE'];
        ADDRESS = this['ADDRESS'];
        var html = "<tr><td>" + ID + "</td><td>" + NAME + "</td><td>" + PHONE + "</td><td>" + ADDRESS + "</td></tr>";
        $(html).appendTo("table");
    });*/

    //var jsonObject = $.parseJSON(data);   
    //alert("ajax call complete");
} //END OF SUCCESS CALL FUNCTION

}）; // END OF .READY

PHP代码

class dbClass {


    private $host = "localhost";
    private $username = "root";
    private $password = "";
    private $schema = "formtest";
    public $dbCon;

    function __construct() {

        $this->dbCon = new mysqli($this->host,$this->username,$this->password,$this->schema);
        if ($this->dbCon->connect_error) {
            die("Issue Connecting: " . $dbCon->connect_errorno . "Error: " . $dbCon->connect_error);
        }
        //var_dump($dbCon);

    }
    function saveDBRecord($dbName, $dbPhone, $dbAddress) {
        //HOW TO FIGURE THIS OUT
        $query = $this->dbCon->prepare("INSERT INTO contact (contact_name,contact_phone,contact_address) VALUES (?,?,?)");
        $query->bind_param("sss",$dbName,$dbPhone,$dbAddress);
        //var_dump($query);
        $query->Execute();

        $recordData = $this->grabRecords();
        return $recordData;
    }

    function grabRecords() {
        $query = $this->dbCon->query("SELECT * FROM contact;");
        //var_dump($query);
        $data = array();
        $counter = 0;
        $i = 0;
        while($row = $query->fetch_row())
        {   
            $record = array(
                "ID" => $row[0],
                "NAME" => $row[1],
                "PHONE" => $row[2],
                "ADDRESS" => $row[3]
                );
        $data[] = $record;
        //$data[$i++] = "ID: {$row[0]} NAME: {$row[1]} PHONE: {$row[2]} ADDRESS: $row[3]";
        //$data .= "ID: {$row[0]} NAME: {$row[1]} PHONE: {$row[2]} ADDRESS: $row[3]";
        //$counter .= $counter;//var_dump($data);
        //$assoc = $query->fetch_all();
        //var_dump($assoc);
        //return $assoc;
        }
        //var_dump($data);

        return $data;

    }

    function __destruct() {
        $this->dbCon->close();
    }

} //END OF dbClass

$dbClassConnection = new dbClass();

/*function displayRecords($recordData) {
//var_dump($recordData[0]);
}*/
//$name = $_POST['name'];
//$phone = $_POST['phone'];
//$address = $_POST['address'];
//$name = "AutoInput";
//$phone = "AutoInput";
//$address = "AutoInput";

//var_dump($dbClassConnection);
if ($_POST['name'] == "" || $_POST['phone'] == "" || $_POST['address'] == "") {

    $recordData = $dbClassConnection->grabRecords()
    echo json_encode($recordData);

    //echo json_encode("HELLO");
    //$recordData = $dbClassConnection->grabRecords();
    //echo json_encode("FIRST IF");
    //var_dump($recordData);
} else {
    $name = $_POST['name'];
    $phone = $_POST['phone'];
    $address = $_POST['address'];

    $recordData = $dbClassConnection->saveDBRecord($name,$phone,$address);
    //$jsonData = displayRecords($recordData);
    //var_dump(json_encode($recordData);
    echo json_encode($recordData);
    //var_dump($jsonData);
    //echo json_encode("SECOND IF");
    //var_dump($recordData);
}

//$name = $_POST['name'];
//ar_dump($name;
//echo json_encode($_POST);

//IF SUBMIT TRUE
//saveDBRecord and grabRecords
//ELSE
//JUST GrabRecords

＆GT;

Answer 1

问题是ajaxCall onLoad也需要序列化formData，然后问题是我如何处理IF语句的POST数据。

AJAX抓取和保存记录的问题

1 个答案: