我正在构建一些自定义列表视图,然后将它们添加到View Pager 但是当我快速浏览屏幕时,View Pager只显示1个自定义ListView。
这是问题的形象:
SpeakingActivity.java
public class SpeakingActivity extends SherlockFragmentActivity {
static final int NUM_ITEMS = 4;
MyAdapter mAdapter;
ViewPager mPager;
@Override
protected void onCreate(Bundle savedInstanceState){
setTheme(R.style.Theme_Sherlock); // Used for theme switching in samples
super.onCreate(savedInstanceState);
setContentView(R.layout.fragment_pager);
mAdapter = new MyAdapter(getSupportFragmentManager());
mPager = (ViewPager) findViewById(R.id.pager);
mPager.setAdapter(mAdapter);
}
public class MyAdapter extends FragmentPagerAdapter {
SpeakingFragment myFrag[];
int numItem = 4;
public MyAdapter(FragmentManager fm) {
super(fm);
myFrag = new SpeakingFragment[numItem];
for(int i = 0; i < numItem; i++) {
myFrag[i] = new SpeakingFragment();
}
}
@Override
public int getCount(){
return numItem;
}
@Override
public Fragment getItem(int position){
return myFrag[position];
}
}
SpeakingFragment.java
public class SpeakingFragment extends SherlockFragment {
public final String KEY_SONG = "song";
public final String KEY_ID = "id";
public final static String KEY_TITLE = "title";
public final static String KEY_ARTIST = "artist";
public final static String KEY_DURATION = "duration";
public final static String KEY_THUMB_URL = "thumb_url";
ListView list;
LazyAdapter adapter;
ArrayList<HashMap<String, String>> songsList;
@Override
public void onCreate(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
}
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState){
View v = inflater.inflate(R.layout.main, container, false);
return v;
}
@Override
public void onActivityCreated(Bundle savedInstanceState){
super.onActivityCreated(savedInstanceState);
list = (ListView) getSherlockActivity().findViewById(R.id.list);
songsList = new ArrayList<HashMap<String, String>>();
for(int i = 0; i < 15; i++) {
HashMap<String, String> map = new HashMap<String, String>();
map.put(KEY_ID, String.valueOf(i));
map.put(KEY_TITLE, "Title" + i);
map.put(KEY_ARTIST, "Dolphin");
map.put(KEY_DURATION, "11:11");
map.put(KEY_THUMB_URL, "Thumb");
songsList.add(map);
}
adapter = new LazyAdapter(getSherlockActivity(), songsList);
list.setAdapter(adapter);
list.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id){
}
});
}
}
LazyAdapter.java
public class LazyAdapter extends BaseAdapter {
private Activity activity;
private ArrayList<HashMap<String, String>> data;
private LayoutInflater inflater = null;
public ImageLoader imageLoader;
public LazyAdapter(Activity a, ArrayList<HashMap<String, String>> d) {
activity = a;
data = d;
inflater = (LayoutInflater) activity.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
imageLoader = new ImageLoader(activity.getApplicationContext());
}
public int getCount(){
return data.size();
}
public Object getItem(int position){
return position;
}
public long getItemId(int position){
return position;
}
public View getView(int position, View convertView, ViewGroup parent){
View vi = convertView;
if(convertView == null) vi = inflater.inflate(R.layout.list_row, null);
TextView title = (TextView) vi.findViewById(R.id.title); // title
TextView artist = (TextView) vi.findViewById(R.id.artist); // artist name
TextView duration = (TextView) vi.findViewById(R.id.duration); // duration
ImageView thumb_image = (ImageView) vi.findViewById(R.id.list_image); // thumb image
HashMap<String, String> song = new HashMap<String, String>();
song = data.get(position);
title.setText(song.get(SpeakingFragment.KEY_TITLE));
artist.setText(song.get(SpeakingFragment.KEY_ARTIST));
duration.setText(song.get(SpeakingFragment.KEY_DURATION));
imageLoader.DisplayImage(song.get(SpeakingFragment.KEY_THUMB_URL), thumb_image);
return vi;
}
}
您可以尝试完整代码here
答案 0 :(得分:1)
我发现了自己的错误 在onActivityCreated之前的迅速行动。它使得下一个片段没有显示,但是当快速返回时,onActivityCreated出现,因此它出现 要修复此错误,请将代码从onActivityCreated更改为onCreateView(因为onCreateView会在swift之前发生)。