将这两个SQL语句合并为一个的最佳方法是什么?我尝试使用union,但似乎无处可去。
select id as id from likes where type=1;
select sum(votes) as votes from likes where parent=id;
这是likes
表:
id type parent country votes
1 1 0 US 0
2 2 1 US 6 // This +
19 3 1 US 3 // This
3 3 2 US 3
7 3 2 US 3
4 10 3 US 1
5 10 3 US 1
6 10 3 US 1
10 10 7 US 1
9 10 7 US 1
8 10 7 US 1
20 10 19 US 1
21 10 19 US 1
22 10 19 US 1
这是我想要实现的结果:
id | votes
---------------
1 | 9
答案 0 :(得分:5)
试试这个:
SELECT
l1.id,
SUM(l2.votes) AS Totalvotes
FROM likes AS l1
INNER JOIN likes AS l2 ON l1.id = l2.parent
WHERE l1.type = 1
GROUP BY l1.id;
请在此处查看:
这会给你:
| ID | TOTALVOTES |
-------------------
| 1 | 9 |
答案 1 :(得分:2)
SELECT SUM(votes) AS votes
FROM likes
WHERE parent IN (SELECT id FROM likes WHERE type=1)
HTH
答案 2 :(得分:1)
这可以解决你的问题,我相信:
SELECT parent AS id, SUM(votes) AS votes FROM likes WHERE parent IN (SELECT id FROM likes WHERE type = 1) GROUP BY parent;
答案 3 :(得分:0)
你可以试试这个
select id,sum(votes) as votes from likes where type=1 and parent=id;
希望这有帮助