我可以制作较小的最后2个数字,但我希望它们显示如下图所示。
TextView TV = (TextView)findViewById(R.id.txt);
Spannable WordtoSpan = new SpannableString("13.500,27");
WordtoSpan.setSpan( new TextAppearanceSpan(null, 0, 12, null, null), WordtoSpan.length()-2, WordtoSpan.length(), Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
TV.setText(WordtoSpan);
谢谢塔尔
答案 0 :(得分:4)
修改强>
您可以使用SuperscriptSpan()
Spannable WordtoSpan = new SpannableString("13.500,27");
WordtoSpan.setSpan( new TextAppearanceSpan(null, 0, 17, null, null), WordtoSpan.length()-2, WordtoSpan.length(), Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
WordtoSpan.setSpan( new SuperscriptSpan(), WordtoSpan.length()-2, WordtoSpan.length(), Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
增加字体大小以查看效果
试试这个 我没有找到任何其他方法,但将上标文本附加到原始的spannalbe字符串
应用跨越SpannableStringBuilder的所需内容
SpannableStringBuilder builder=new SpannableStringBuilder("13.500,");
builder.append(Html.fromHtml("X<sup>27</sup>"))
修改2
如果你创建如下所示的自定义范围,它绝对将supertext与top对齐。但是如果你使用默认的SuperscriptSpan,它就无法使文本成为顶级。
public class SuperscriptSpan2 extends MetricAffectingSpan implements
ParcelableSpan {
public SuperscriptSpan2() {
}
public int getSpanTypeId() {
return TextUtils.CAP_MODE_CHARACTERS;
}
public int describeContents() {
return 0;
}
public void writeToParcel(Parcel dest, int flags) {
}
@Override
public void updateDrawState(TextPaint tp) {
tp.baselineShift += (int) (tp.ascent() / 1.25);
}
@Override
public void updateMeasureState(TextPaint tp) {
tp.baselineShift += (int) (tp.ascent() / 1.25);
}
}