Question

我有可存储每日内容选择的数据。每天都有所不同。

当我选择超过一天时，我需要退回所有日子都相同的项目。

我尝试过这样的事情：

SELECT * FROM
                        (
                             SELECT
                                ( -- For count
                                SELECT COUNT(recipeId) AS [Count]
                                FROM DailyContentDish
                                WHERE
                                    (
                                        (weekDayId=@mon OR @mon IS NULL) OR
                                        (weekDayId=@tue OR @tue IS NULL) OR
                                        (weekDayId=@wed OR @wed IS NULL) OR
                                        (weekDayId=@thu OR @thu IS NULL) OR
                                        (weekDayId=@fri OR @fri IS NULL) OR
                                        (weekDayId=@sat OR @sat IS NULL) OR
                                        (weekDayId=@sun OR @sun IS NULL) 
                                    ) 
                                    GROUP BY DailyContentDish.recipeId
                                ) AS cnt, 
                                -- End for count
                                DailyContentDish.dailyContentDishId,
                                DailyContentDish.recipeId AS Rec, 
                                title, 
                                150 AS calories, 
                                defaultSmallImagePath,
                                activePreparationTime + passivePreparationTime AS overallPreparationTime,
                                CAST(
                                    CASE WHEN EXISTS
                                        (
                                        SELECT  DailyContentDishFavourite.dailyContentDishFavouriteId
                                        FROM DailyContentDishFavourite 
                                        WHERE DailyContentDishFavourite.dailyContentDishId = DailyContentDish.dailyContentDishId
                                        )
                                    THEN 1 
                                    ELSE 0
                                END 
                                AS BIT) AS isFavouriteWhenGeneratingMenu


                                FROM DailyContentDish
                                LEFT OUTER JOIN
                                    RecipesTranslations ON RecipesTranslations.recipeId = DailyContentDish.recipeId
                                LEFT OUTER JOIN
                                    RecipeAdditionalInformation ON RecipeAdditionalInformation.recipeId = DailyContentDish.recipeId
                    WHERE
                    isEnabled = 1 AND
                    mealId=@mealId AND 
                        (       
                                weekDayId=@mon OR
                                weekDayId=@tue OR
                                weekDayId=@wed OR
                                weekDayId=@thu OR
                                weekDayId=@fri OR
                                weekDayId=@sat OR
                                weekDayId=@sun
                                )

                            ) p
                            WHERE p.cnt = @daysCount

问题是，应该返回count的嵌套select会为所有行返回它，而不仅仅是一个条目（每一行）。由于输入了recipeId的条目多了一次，我想知道它们输入了多少次。

SELECT
                                ( -- For count
                                SELECT COUNT(recipeId) AS [Count]
                                FROM DailyContentDish
                                WHERE
                                    (
                                        (weekDayId=@mon OR @mon IS NULL) OR
                                        (weekDayId=@tue OR @tue IS NULL) OR
                                        (weekDayId=@wed OR @wed IS NULL) OR
                                        (weekDayId=@thu OR @thu IS NULL) OR
                                        (weekDayId=@fri OR @fri IS NULL) OR
                                        (weekDayId=@sat OR @sat IS NULL) OR
                                        (weekDayId=@sun OR @sun IS NULL) 
                                    )  AND Something should be here (I guess)
                                    GROUP BY DailyContentDish.recipeId
                                ) AS cnt, 
                                -- End for count

此部分应为我选择的每一行返回COUNT个条目 - 但它会将所有条目的COUNT重新归还。

或者我应该采取不同的方式。任何提示都非常感谢。

我正在使用MS SQL Server 2008

编辑：这是整个存储过程：

        @userId int,
        @languageId int,
        @mealId int,
        @mon int,
        @tue int,
        @wed int,
        @thu int,
        @fri int,
        @sat int,
        @sun int,
        @orderBy nvarchar(2),
        @pageSize int,
        @startRowIndex int

AS
BEGIN

SET NOCOUNT ON;

DECLARE @daysCount int
SET @daysCount = 0
IF (@mon IS NOT NULL)
    BEGIN
        SET @daysCount = @daysCount+1
    END
IF (@tue IS NOT NULL)
    BEGIN
        SET @daysCount = @daysCount+1
    END
IF (@wed IS NOT NULL)
    BEGIN
        SET @daysCount = @daysCount+1
    END
IF (@thu IS NOT NULL)
    BEGIN
        SET @daysCount = @daysCount+1
    END
IF (@fri IS NOT NULL)
    BEGIN
        SET @daysCount = @daysCount+1
    END
IF (@sat IS NOT NULL)
    BEGIN
        SET @daysCount = @daysCount+1
    END
IF (@sun IS NOT NULL)
    BEGIN
        SET @daysCount = @daysCount+1
    END


-- Insert statements for procedure here
    SELECT *
    FROM (
SELECT
    (
        SELECT [Count] = COUNT(recipeId) 
        FROM dbo.DailyContentDish d
        WHERE
        (
            ISNULL(@mon, weekDayId) = weekDayId OR
            ISNULL(@tue, weekDayId) = weekDayId OR
            ISNULL(@wed, weekDayId) = weekDayId OR
            ISNULL(@thu, weekDayId) = weekDayId OR
            ISNULL(@fri, weekDayId) = weekDayId OR
            ISNULL(@sat, weekDayId) = weekDayId OR
            ISNULL(@sun, weekDayId) = weekDayId 
        ) 
        GROUP BY d.recipeId
    ) AS cnt, 
    d.dailyContentDishId,
    d.recipeId AS Rec, 
    title, 
    150 AS calories, 
    defaultSmallImagePath,
    activePreparationTime + passivePreparationTime AS overallPreparationTime,
    CASE WHEN d2.dailyContentDishId IS NULL THEN 1 ELSE 0 END AS isFavouriteWhenGeneratingMenu
FROM dbo.DailyContentDish d
LEFT JOIN dbo.RecipesTranslations r ON r.recipeId = d.recipeId
LEFT JOIN dbo.RecipeAdditionalInformation t ON t.recipeId = d.recipeId
LEFT JOIN dbo.DailyContentDishFavourite d2 ON d.dailyContentDishId = d2.dailyContentDishId
WHERE isEnabled = 1 
    AND mealId = @mealId 
    AND (       
        weekDayId = @mon OR
        weekDayId = @tue OR
        weekDayId = @wed OR
        weekDayId = @thu OR
        weekDayId = @fri OR
        weekDayId = @sat OR
        weekDayId = @sun
    )
    ) p
    WHERE p.cnt = @daysCount

Edit1：我上传了图表： Database diagram

以下是样本数据（用餐ID = 1，也在表格中选择），说明： - ID为125的食谱将在星期一（weekDayId = 1）和星期六（weekDayId = 7）出现。因此，如果我只选择星期一，或者如果我只选择星期六，或者如果我选择星期一和星期六，则必须返回此食谱。如果我也选择任何其他日子，则不会返回ithis记录。 - 选择周日1,6和7（周一，周六，周日）时，必须返回ID为105的食谱。与上述相同，如果选择任何其他日期，则不会返回此记录。 Sample data

Answer 1

这可能对您有帮助 -

ALTER PROCEDURE dbo.usp_GetDailyContentDish

    @userId INT,
    @languageId INT,
    @mealId INT,
    @mon INT,
    @tue INT,
    @wed INT,
    @thu INT,
    @fri INT,
    @sat INT,
    @sun INT,
    @orderBy NVARCHAR(2),
    @pageSize INT,
    @startRowIndex INT

AS BEGIN

    SET NOCOUNT ON;

    DECLARE @daysCount INT
    SELECT @daysCount = 
        CASE WHEN @mon IS NOT NULL THEN 1 ELSE 0 END +
        CASE WHEN @tue IS NOT NULL THEN 1 ELSE 0 END +
        CASE WHEN @wed IS NOT NULL THEN 1 ELSE 0 END +
        CASE WHEN @thu IS NOT NULL THEN 1 ELSE 0 END +
        CASE WHEN @fri IS NOT NULL THEN 1 ELSE 0 END +
        CASE WHEN @sat IS NOT NULL THEN 1 ELSE 0 END + 
        CASE WHEN @sun IS NOT NULL THEN 1 ELSE 0 END 

    SELECT
          Rec
        , calories
        , overallPreparationTime
        , isFavouriteWhenGeneratingMenu
    FROM (
        SELECT
            (
                SELECT [Count] = COUNT(d3.recipeId) 
                FROM dbo.DailyContentDish d3
                WHERE
                (
                    ISNULL(@mon, weekDayId) = weekDayId OR
                    ISNULL(@tue, weekDayId) = weekDayId OR
                    ISNULL(@wed, weekDayId) = weekDayId OR
                    ISNULL(@thu, weekDayId) = weekDayId OR
                    ISNULL(@fri, weekDayId) = weekDayId OR
                    ISNULL(@sat, weekDayId) = weekDayId OR
                    ISNULL(@sun, weekDayId) = weekDayId 
                ) AND d3.recipeId = d.recipeId 
                GROUP BY d3.recipeId
            ) AS cnt, 
            d.dailyContentDishId,
            d.recipeId AS Rec, 
            title, 
            150 AS calories, 
            defaultSmallImagePath,
            activePreparationTime + passivePreparationTime AS overallPreparationTime,
            CASE WHEN d2.dailyContentDishId IS NULL THEN 1 ELSE 0 END AS isFavouriteWhenGeneratingMenu
        FROM dbo.DailyContentDish d
        LEFT JOIN dbo.RecipesTranslations r ON r.recipeId = d.recipeId
        LEFT JOIN dbo.RecipeAdditionalInformation t ON t.recipeId = d.recipeId
        LEFT JOIN dbo.DailyContentDishFavourite d2 ON d.dailyContentDishId = d2.dailyContentDishId
        WHERE isEnabled = 1 
            AND mealId = @mealId 
            AND (       
                weekDayId = @mon OR
                weekDayId = @tue OR
                weekDayId = @wed OR
                weekDayId = @thu OR
                weekDayId = @fri OR
                weekDayId = @sat OR
                weekDayId = @sun
            )
    ) p
    WHERE p.cnt = @daysCount

END

小型顶部：

此：

AND (       
    weekDayId = @mon OR
    weekDayId = @tue OR
    weekDayId = @wed OR
    weekDayId = @thu OR
    weekDayId = @fri OR
    weekDayId = @sat OR
    weekDayId = @sun
)

可能优化：

weekDayId % @weekDay = 0

如果@mon，@ tue 不为空且包含1,2，......

Answer 2

SELECT *
FROM (
      SELECT
        ( -- For count
         SELECT COUNT(d.recipeId) AS [Count]
         FROM DailyContentDish d
         WHERE (
                ISNULL(@amon, d.weekDayId) = d.weekDayId OR
                ISNULL(@tue, d.weekDayId) = d.weekDayId OR
                ISNULL(@wed, d.weekDayId) = d.weekDayId OR
                ISNULL(@thu, d.weekDayId) = d.weekDayId OR
                ISNULL(@fri, d.weekDayId) = d.weekDayId OR
                ISNULL(@sat, d.weekDayId) = d.weekDayId OR
                ISNULL(@sun, d.weekDayId) = d.weekDayId 
                ) AND d.recipeId = DailyContentDish.recipeId
          GROUP BY d.recipeId
          ) AS cnt, 
          -- End for count
          DailyContentDish.dailyContentDishId,
          DailyContentDish.recipeId AS Rec, 
          title, 
          150 AS calories, 
          defaultSmallImagePath,
          activePreparationTime + passivePreparationTime AS overallPreparationTime,
          CAST(
               CASE WHEN EXISTS
               (
                SELECT  DailyContentDishFavourite.dailyContentDishFavouriteId
                FROM DailyContentDishFavourite 
                WHERE DailyContentDishFavourite.dailyContentDishId = DailyContentDish.dailyContentDishId
                )
                    THEN 1 
                    ELSE 0
                END 
                AS BIT) AS isFavouriteWhenGeneratingMenu
         FROM DailyContentDish
           LEFT OUTER JOIN
             RecipesTranslations ON RecipesTranslations.recipeId = DailyContentDish.recipeId
           LEFT OUTER JOIN
             RecipeAdditionalInformation ON RecipeAdditionalInformation.recipeId = DailyContentDish.recipeId
         WHERE
           isEnabled = 1 AND
           mealId=@mealId AND 
             (       
              weekDayId=@mon OR
              weekDayId=@tue OR
              weekDayId=@wed OR
              weekDayId=@thu OR
              weekDayId=@fri OR
              weekDayId=@sat OR
              weekDayId=@sun
              )        
        ) p
WHERE p.cnt = @daysCount

更新21.05.2013（已添加演示）

IF OBJECT_ID('tempdb.dbo.#weekDays') IS NOT NULL DROP TABLE dbo.#weekDays     
SELECT weekDayId
INTO dbo.#weekDays
FROM(VALUES(@mon),
           (@tue),
           (@wed),
           (@thu),
           (@fri),
           (@sat),
           (@sun))x(weekDayId)
WHERE weekDayId IS NOT NULL

CREATE UNIQUE CLUSTERED INDEX x ON dbo.#weekDays(weekDayId)

SELECT d.dailyContentDishId,
       d.recipeId AS Rec, 
       title, 
       150 AS calories, 
       defaultSmallImagePath,
       activePreparationTime + passivePreparationTime AS overallPreparationTime,
       CASE WHEN f.dailyContentDishId IS NULL THEN 1 ELSE 0 END AS isFavouriteWhenGeneratingMen
FROM DailyContentDish d
  LEFT JOIN RecipesTranslations ON RecipesTranslations.recipeId = d.recipeId
  LEFT JOIN RecipeAdditionalInformation ON RecipeAdditionalInformation.recipeId = d.recipeId
  LEFT JOIN dbo.DailyContentDishFavourite f ON d.dailyContentDishId = f.dailyContentDishId
WHERE d.isEnabled = 1 AND d.mealId = @mealId 
  AND NOT EXISTS(          
                 SELECT d3.weekDayId
                 FROM dbo.#weekDays d3
                 EXCEPT
                 SELECT d2.WeekDayId
                 FROM DailyContentDish d2
                 WHERE d.recipeId = d2.recipeId 
                   AND d2.isEnabled = 1 AND d2.mealId = @mealId 
                 )

SQLFiddle

上的简单演示

Answer 3

只有当天（和用餐）相同的膳食应该是返回

缺少的是外部查询与内部查询中的计数计算的相关性。即以下内容：

( DC1.WeekDayId In( @Mon, @Tue, @Wed, @Thu, @Fri, @Sat, @Sun )
    Or Coalesce( @Mon, @Tue, @Wed, @Thu, @Fri, @Sat, @Sun ) Is Null )
And DC1.MealId = DC.MealId

您需要对至少一个表进行别名才能实现此目的。通常，如果在内部和外部查询上对表进行别名，则更容易阅读。缺少的另一个项目是每天的七个变量代表刻度（＆＃34;选择这一天＆＃34;）而不是一天本身。如果我们改变它，它会使查询更简单。

Select @Mon = Case When @Mon Is Not Null Then 1 End
    , @Tue = Case When @Tue Is Not Null Then 2 End
    , @Wed = Case When @Wed Is Not Null Then 3 End
    , @Thu = Case When @Thu Is Not Null Then 4 End
    , @Fri = Case When @Fri Is Not Null Then 5 End
    , @Sat = Case When @Sat Is Not Null Then 6 End
    , @Sun = Case When @Sun Is Not Null Then 7 End;

 Select Count(*) Over() As CountOfResults
    ,   (
        Select Count(*)
        From DailyContentDish As DC1
        Where DC1.weekDayId = DC.weekDayId
        ) As CountOfDishesOnDay
    ,   (
        Select Count(Distinct mealId)
        From DailyContentDish As DC1
        Where DC1.weekDayId = DC.weekDayId
        ) As CountOfMeals           
    , DC.DailyContentDishId
    , DC.RecipeId As Rec
    , Title
    , 150 As Calories
    , DefaultsMallImagePath
    , ActivePreparationTime 
        + PassivePreparationTime As OverallPreparationTime
    , Cast  (
            Case 
            When Exists (
                        Select 1
                        From DailyContentDishFavourite As DF1
                        Where DF1.DailyContentDishId = DC.DailyContentDishId
                        ) Then 1 
            Else 0
            End 
            As Bit) As IsFavouriteWhenGeneratingMenu
From DailyContentDish As DC
    Left Join RecipesTranslations As RT
        On RT.RecipeId = DC.RecipeId
    Left Join RecipeAdditionalInformation As RA
        On RA.RecipeId = DC.RecipeId
Where DC.IsEnabled = 1 
    And DC.MealId=@MealId 
    And DC.WeekDayId In( @Mon, @Tue, @Wed, @Thu, @Fri, @Sat, @Sun )

<强>加成

如果每日变量应该代表每天返回的结果计数（例如，如果@Mon = 2，那么我们应该在星期一返回两行），然后你可以这样做：

Declare @DailyParameters Table
    (
    DayCount int not null
    , DayOfWeek int not null
    )

Insert @DailyParameters( DayCount, DayOfWeek )
Select Z.Cnt, Z.DayOfWeek
From    (
        Select @Mon As Cnt, 1 As DayOfWeek
        Union All Select @Tue, 2
        Union All Select @Wed, 3
        Union All Select @Thu, 4
        Union All Select @Fri, 5
        Union All Select @Sat, 6
        Union All Select @Sun, 7
        ) As Z
Where Z.Cnt Is Not Null

然后Where子句会改为：

Where DC.IsEnabled = 1 
    And DC.MealId = @MealId 
    And DC.WeekDayId In( Select DayOfWeek From @DailyParameters )
    And (
        Select Count(*)
        From DailyContentDish As DC1
        Where DC1.weekDayId = DC.weekDayId
        ) = (
            Select D1.DayCount
            From @DailyParameters As D1
            Where D1.DayOfWeek = DC.weekDayId
            )

Answer 4

“由于输入了recipeId的条目多了一次，我想知道它们输入了多少次。”

基于这个陈述，我只会将OVER子句与COUNT一起使用。

类似的东西：

SELECT
  COUNT(*) OVER (PARTITION BY recipeId) AS 'cnt'
  FROM DailyContentDish

我需要有关表的更多详细信息以及输出应该是什么，以便提供更多详细信息。

以下是2008年OVER条款的更多信息：http://msdn.microsoft.com/en-us/library/ms189461(v=sql.105).aspx

使用COUNT与OVER的示例：http://blog.sqlauthority.com/2011/08/11/sql-server-tips-from-the-sql-joes-2-pros-development-series-advanced-aggregates-with-the-over-clause-day-11-of-35/

数据表中每行的SELECT COUNT（外部ID）

4 个答案: