Question

我有一个课程，从过去的时间起充当时钟，可以以不同的速度播放。在下面的示例代码中，我正在以60x播放。

我注意到时间每10秒左右漂移一次，我想知道如何处理它。

import java.util.Calendar;

public class Clock {

    long delta;
    long lastCalledTime;
    long startingTime;
    private float speed = 1f;

    public synchronized long getAdjustedTimeMillis() {
        long time = (System.currentTimeMillis() - (delta));
        long val = (startingTime + (long) ((time - lastCalledTime) * speed));
        return val;
    }

    public synchronized void setPlaybackSpeedFromTime(float speed, long startingTime) {
        this.startingTime = startingTime;
        this.delta = System.currentTimeMillis() - startingTime;
        this.speed = speed;
        this.lastCalledTime = System.currentTimeMillis() - delta;
    }

    public static void main(String[] args) {
        Calendar calendar = Calendar.getInstance();
        calendar.set(2010, 4, 4, 4, 4, 4);
        Clock clock = new Clock();
        clock.setPlaybackSpeedFromTime(60f, calendar.getTimeInMillis());
        for (int i = 0; i < 1000; i++) {
            calendar.setTimeInMillis(clock.getAdjustedTimeMillis());
            System.out.println(calendar.getTime());
            try {
                Thread.sleep(1000);
            } catch (InterruptedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }


    }

}

以下是我得到的输出：

Tue May 04 04:04:04 PDT 2010
Tue May 04 04:05:06 PDT 2010
Tue May 04 04:06:06 PDT 2010
Tue May 04 04:07:06 PDT 2010
Tue May 04 04:08:06 PDT 2010
Tue May 04 04:09:06 PDT 2010
Tue May 04 04:10:06 PDT 2010
Tue May 04 04:11:06 PDT 2010
Tue May 04 04:12:06 PDT 2010
Tue May 04 04:13:07 PDT 2010
Tue May 04 04:14:07 PDT 2010
Tue May 04 04:15:07 PDT 2010
Tue May 04 04:16:07 PDT 2010
Tue May 04 04:17:07 PDT 2010
Tue May 04 04:18:07 PDT 2010
Tue May 04 04:19:07 PDT 2010
Tue May 04 04:20:07 PDT 2010
Tue May 04 04:21:07 PDT 2010
Tue May 04 04:22:07 PDT 2010
Tue May 04 04:23:08 PDT 2010
Tue May 04 04:24:08 PDT 2010

正如你所看到的“秒”漂移。我想要的是这个：

Tue May 04 04:04:04 PDT 2010
Tue May 04 04:05:04 PDT 2010
Tue May 04 04:06:04 PDT 2010
Tue May 04 04:07:04 PDT 2010
Tue May 04 04:08:04 PDT 2010
Tue May 04 04:09:04 PDT 2010
Tue May 04 04:10:04 PDT 2010
Tue May 04 04:11:04 PDT 2010
Tue May 04 04:12:04 PDT 2010
Tue May 04 04:13:04 PDT 2010
Tue May 04 04:14:04 PDT 2010
Tue May 04 04:15:04 PDT 2010
Tue May 04 04:16:04 PDT 2010
Tue May 04 04:17:04 PDT 2010
Tue May 04 04:18:04 PDT 2010
Tue May 04 04:19:04 PDT 2010
Tue May 04 04:20:04 PDT 2010
Tue May 04 04:21:04 PDT 2010
Tue May 04 04:22:04 PDT 2010
Tue May 04 04:23:04 PDT 2010
Tue May 04 04:24:04 PDT 2010

Answer 1

只需将时间基于您知道准确的来源......对于临时应用，系统时钟通常足够好。如果您尝试让您的应用帐户占用时间，那么您的精度将受到JVM的并发稳健性的限制。而且，老实说，这不是JVM打算做得好的事情。

Answer 2

由于您的流程正在处理其他操作已经过了一段时间，因此您有时间漂移。而不是Thread.sleep(int)，请尝试java.util.Timer.scheduleAtFixedRate(task, date, period)。 Timer内部计算下一个执行时间并在指定时间触发。这个触发也是由Timer使用wait-notify锁定机制在内部完成的。简而言之，您必须实现更新时钟的TimerTask，然后使用Timer以所需的时间间隔（例如1000ms）安排任务。

Answer 3

为什么不直接使用系统时钟？

initialStartTime = System.currentTimeMillis();
while (true){
    if (intialStartTime - System.currentTimeMillis() % 1000 == 0){
        System.out.println(calendar.getTime());
    }
}

显然，你需要在后台线程上运行上面的代码，而不是while（true）有一些合理的退出条件。 SO上有关于线程等的大量信息。

Java：时间漂移

3 个答案: