无法回显php类变量

时间:2013-05-16 21:42:01

标签: php class variables

我想写一个php简单的分页类。这是我的代码:

<?php
class Pagination {
public $rowsPerPage;
public $currentPage;
public $totalPages;
public $totalRows;
public $firstElement;
public $lastElement;


     public function paginate()
        { 
            if(isset($_GET['page'])){
                $this->currentPage  = $_GET['page'];     
            }           

                         $this->totalPages =  $this->totalRows/$this->rowsPerPage  ;
             return $this->totalPages;  

              $this->firstElement = $this->currentPage-1)*$this->rowsPerPage+1;
              return $this->firstElement;                
        }
}

$totalRecords = 55;
$paginator = new Pagination();
$paginator->totalRows = $totalRecords;
$paginator->rowsPerPage = 5;
$paginator->paginate();
echo $paginator->totalPages;
echo $paginator->firstElement;  
?>

我可以回复$ paginator-&gt; totalPages;但不是$ paginator-&gt; firstElement。 我做错了什么? 感谢

1 个答案:

答案 0 :(得分:8)

您的paginate函数有两个return语句。

当代码命中return $this->totalPages;时,它将停止运行该功能。因此,$this->firstElement = ...行永远不会运行。