Question

我已经制作了一段时间的javascript计算器，我可以获得所有基本功能和pow（）函数，但是我无法让它做Math.sqrt（）函数。过去几天我遇到了这个问题。这是我的代码，提前谢谢：

function calc()
{
    var D = "";
    var A = document.getElementById("num1").value;
    var B = document.getElementById("op").value;
    var C = document.getElementById("num2").value;
    X = parseInt(A);
    S = 2
    var Z = "If you're seeing this, that means that the code isn't working!!"
    D = eval(A + B + C);
    if (B == "%")
    {
        D = ""
        Z = Math.sqrt(X)*1
    }
    else if (B == "^")
    {
        D = ""
        Z = Math.pow(X, C)
    }
    else if (B == "^2")
    {
        D = ""
        Z = Math.pow(X, S)
    }
    else if (B == "")
    {
        D = "No Operator"
        Z = ""
    }
    document.getElementById("result").value = D;
    document.getElementById("sqrt-result").value = Z;       
    return false;
}

Answer 1

我刚测试过它，你的代码运行正常。我的假设是你试图使用平方根功能而不是在num2中放置任何东西，这对于计算数字的平方根来说似乎很自然。但是，如果您打开错误控制台，当您尝试在操作员之后没有任何内容进行评估时，您会注意到eval不喜欢它。我的建议是将eval移到if以下，以便只有在需要时才会使用。

function calc()
{
    var D = "";
    var A = document.getElementById("num1").value;
    var B = document.getElementById("op").value;
    var C = document.getElementById("num2").value;
    X = parseInt(A);
    S = 2
    var Z = "If you're seeing this, that means that the code isn't working!!"
    if (B == "%")
    {
        Z = Math.sqrt(X)*1
    }
    else if (B == "^")
    {
        Z = Math.pow(X, C)
    }
    else if (B == "^2")
    {
        Z = Math.pow(X, S)
    }
    else if (B == "")
    {
        D = "No Operator"
        Z = ""
    } else {
        // Only do this if not doing any of the above calculations
        D = eval(A + B + C);
    }
    document.getElementById("result").value = D;
    document.getElementById("sqrt-result").value = Z;       
    return false;
}

Javascript计算器中的Square-Rooting不显示

1 个答案: