我在第1行中有上述数据(即单元格A1,单元格B1,单元格C1等)。
我想找到包含2013年4月的单元格的列号。
这是我的代码:
MsgBox Application.Match("Apr 2013", Range("1:1"), 1)
返回不匹配错误。知道出了什么问题吗?
答案 0 :(得分:2)
你试试这个:
Sub main()
Dim stringToMatch$
stringToMatch = "Apr 2013"
Call DisplayMatchingColumnNumber(ActiveSheet, stringToMatch)
End Sub
Sub DisplayMatchingColumnNumber(ByRef ws As Worksheet, str$)
Dim i&, x$
For i = 1 To ws.Cells(1, Columns.Count).End(xlToLeft).Column
x = Right(CStr(ws.Cells(1, i).Value), 8)
If StrComp(x, str, vbTextCompare) = 0 Then
MsgBox "the column number is: " & i
End If
Next i
End Sub
<小时/> <小时/> 正如Microsoft所说:
Arg2 is Required of type Variant
Lookup_array - a contiguous range of cells containing possible lookup values.
Lookup_array must be an array or an array reference.
因此:
Sub ReadAboutFunctionsYouAreUsing()
Dim x
x = Array("Apr 2013", "Mar 2013", "Feb 2013")
MsgBox Application.Match("Apr 2013", x, 1)
End Sub
<小时/> <小时/> 用户定义的功能
=getColumnNumber("Apr 2013")
Function getColumnNumber(str$)
Dim i&, x$
For i = 1 To ActiveSheet.Cells(1, Columns.Count).End(xlToLeft).Column
x = Right(CStr(ActiveSheet.Cells(1, i).Value), 8)
If StrComp(x, str, vbTextCompare) = 0 Then
getColumnNumber = i
End If
Next i
End Function
答案 1 :(得分:1)
我在VBA中经常遇到这种情况,尤其是日期。这就是我要做的事情:
Dim tmpRng As Range
Set tmpRng = ActiveWorkbook.Worksheets("Sheet1").Range("AA:650") 'or some other unused cell
tmpRng.Value = "Apr 2013"
MsgBox Application.Match(tmpRng, Range("1:1"), 1)
tmpRng.Value = ""
出于某种原因,Match似乎喜欢将单元格引用作为其第一个参数。