Question

我有一个bash函数，比如foo ()

我在user=user1 pass=pwd address=addr1 other=这样的字符串中传递了一些参数参数可能会被遗漏或以随机序列传递我需要在foo

中分配适当的值

USER=...
PASSWORD=...
ADDRESS=...

我该怎么做？

我可以多次使用grep，但这种方式并不好，例如

foo ()
{
  #for USER
  for par in $* ; do 
    USER=`echo $par | grep '^user='` 
    USER=${USER#*=} 
  done
  #for PASSWORD
  for ...
}

Answer 1

这是你的意思吗？

#!/bin/sh
# usage: sh tes.sh username password addr

# Define foo
# [0]foo [1]user [2]passwd [3]addr
foo () {
    user=$1
    passwd=$2
    addr=$3
    echo ${user} ${passwd} ${addr}
}

# Call foo
foo $1 $2 $3

结果：

$ sh test.sh username password address not a data
username password address

您的问题也已在此处得到解答：

Passing parameters to a Bash function

显然上述答案与问题无关，那怎么样？

#!/bin/sh

IN="user=user pass=passwd other= another=what?"

arr=$(echo $IN | tr " " "\n")

for x in $arr
do
    IFS==
    set $x
    [ $1 = "another" ] && echo "another = ${2}"
    [ $1 = "pass" ] && echo "password = ${2}"
    [ $1 = "other" ] && echo "other = ${2}"
    [ $1 = "user" ] && echo "username = ${2}"
done

结果：

$ sh test.sh
username = user
password = passwd
other =
another = what?

解析bash函数参数

1 个答案: