我有下表:
╔══════════╦════════╦═══════╦═══════╗ ║ PlayerID ║ GameID ║ Stat1 ║ Stat2 ║ ╠══════════╬════════╬═══════╬═══════╣ ║ 1 ║ A ║ 2 ║ 1 ║ ║ 1 ║ B ║ 4 ║ 2 ║ ║ 1 ║ C ║ 6 ║ 5 ║ ║ 2 ║ A ║ 2 ║ 4 ║ ║ 2 ║ B ║ 2 ║ 6 ║ ║ 2 ║ C ║ 2 ║ 8 ║ ║ 2 ║ D ║ 4 ║ 2 ║ ║ 2 ║ E ║ 6 ║ 1 ║ ║ 3 ║ A ║ 5 ║ 9 ║ ║ 3 ║ G ║ 6 ║ 4 ║ ║ 3 ║ H ║ 4 ║ 2 ║ ║ 3 ║ N ║ 8 ║ 6 ║ ╚══════════╩════════╩═══════╩═══════╝
我想要实现的目标如下:
╔══════════╦═══════════╦═══════════════════╦═══════════════════╗ ║ PlayerID ║ GameCount ║ Stat 1 Avg / Game ║ Stat 2 Avg / Game ║ ╠══════════╬═══════════╬═══════════════════╬═══════════════════╣ ║ 1 ║ 3 ║ 4 ║ 2.66 ║ ║ 2 ║ 5 ║ 3.2 ║ 4.2 ║ ║ 3 ║ 4 ║ 5.75 ║ 5.25 ║ ╚══════════╩═══════════╩═══════════════════╩═══════════════════╝
游戏数量应该是每位玩家玩游戏的总数,统计数据应该是每场比赛的平均值。基本上,PlayerID 1的计算如下:
“Stat1平均/游戏”=(2 + 4 + 6)/ 3 “Stat2 Avg / Game”=(1 + 2 + 5)/ 3
我尝试过使用SUMS和COUNTS组合的同一查询的多种变体,但GameCount永远不会出错。我尝试过的一个例子如下:
SELECT PlayerID,
COUNT(GameID) AS GameCount,
SUM(Stat1) / COUNT(GameID) "Stat 1 Avg / Game",
SUM(Stat2) / COUNT(GameID) "Stat 2 Avg / Game"
FROM PublishedStats A
GROUP BY PlayerID
SELECT PlayerID,
COUNT(GameID) OVER (PARTITION BY PlayerID) AS GameCount,
SUM(Stat1) / COUNT(GameID) OVER (PARTITION BY PlayerID) "Stat 1 Avg / Game",
SUM(Stat2) / COUNT(GameID) OVER (PARTITION BY PlayerID) "Stat 2 Avg / Game",
FROM Stats
GROUP BY PlayerID, GameID
答案 0 :(得分:0)
所以只需添加DISTINCT关键字。
SELECT PlayerID,
COUNT(DISTINCT GameID) AS GameCount,
AVG(Stat1) "Stat 1 Avg / Game",
AVG(Stat2) "Stat 2 Avg / Game"
FROM PublishedStats A
GROUP BY PlayerID