我有一个由Jackson,Jersey,EclipseLink和Tomcat提供支持的小型RESTful Web服务。在大多数情况下,除了涉及嵌套子元素之外,XML正在按预期工作。当XML文档的其余部分不是时,它们使用命名空间属性编写。以下是响应XML的示例:
<userView>
<userIdSID>5</userIdSID>
<userAuthLevel>5</userAuthLevel>
<userRoles>
<roleSID xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xs="http://www.w3.org/2001/XMLSchema" xsi:type="xs:decimal">1</roleSID>
<roleSID xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xs="http://www.w3.org/2001/XMLSchema" xsi:type="xs:decimal">3</roleSID>
<roleSID xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xs="http://www.w3.org/2001/XMLSchema" xsi:type="xs:decimal">2</roleSID>
<roleSID xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xs="http://www.w3.org/2001/XMLSchema" xsi:type="xs:decimal">8</roleSID>
<roleSID xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xs="http://www.w3.org/2001/XMLSchema" xsi:type="xs:decimal">5</roleSID>
<roleSID xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xs="http://www.w3.org/2001/XMLSchema" xsi:type="xs:decimal">4</roleSID>
<roleSID xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xs="http://www.w3.org/2001/XMLSchema" xsi:type="xs:decimal">9</roleSID>
<roleSID xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xs="http://www.w3.org/2001/XMLSchema" xsi:type="xs:decimal">1000001</roleSID>
</userRoles>
</userView>
这就是我的UserRoleList.java:
package com.company.project;
import java.io.Serializable;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
@XmlAccessorType(XmlAccessType.FIELD)
public class UserRoleList implements Serializable {
private int userRoleSID;
public int getUserRoleSid() {
return userRoleSID;
}
public void setUserRoleSid(int userRoleSid) {
this.userRoleSID = userRoleSid;
}
}
这就是我的UserView.java:
package com.company.project;
import java.io.Serializable;
import java.util.ArrayList;
import java.util.List;
import javax.persistence.Basic;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlElementWrapper;
import javax.xml.bind.annotation.XmlRootElement;
@Entity
@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement
public class UserView implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@Basic(optional = false)
@Column(name = "USER_ID_SID")
private String userIdSID;
@Basic(optional = true)
private String userAuthLevel;
@XmlElementWrapper(name = "userRoles")
@XmlElement(name = "roleSID")
private List<UserRoleList> userRoleList = new ArrayList<UserRoleList>();
public UserView() {
}
public UserView(String userIdSID) {
this.userIdSID = userIdSID;
}
public String getUserIdSID() {
return userIdSID;
}
public void setUserIdSID(String userIdSID) {
this.userIdSID = userIdSID;
}
public List<UserRoleList> getUserRoleList() {
return userRoleList;
}
public void setUserRoleList(List<UserRoleList> userRoleList) {
this.userRoleList = userRoleList;
}
public String getUserAuthLevel() {
return userAuthLevel;
}
public void setUserAuthLevel(String userAuthLevel) {
this.userAuthLevel = userAuthLevel;
}
}
这是我填充nest元素的方式,它需要2个入站参数并通过Entity Manager执行查询:
List<UserRoleList> userRoleList = em.createNamedQuery("findRoleListByLoginName")
.setParameter(1, id)
.setParameter(2, client)
.getResultList();
关于我可能遗失某些东西的任何想法?我尝试过使用pkg-info无济于事。请注意,此输出构造的XML没有从中生成的模式。不确定这是否有帮助或阻碍,但是非常感谢任何帮助。
更新1 :根据要求,这是我的web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<display-name>moxyWS</display-name>
<servlet>
<servlet-name>ServletAdaptor</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<description>Multiple packages, separated by semicolon(;), can be specified in param-value</description>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.project.moxyws</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>ServletAdaptor</servlet-name>
<url-pattern>/webresources/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>30</session-timeout>
</session-config>
<persistence-unit-ref>
<persistence-unit-ref-name>persistence-factory</persistence-unit-ref-name>
<persistence-unit-name>moxyWS_war_1.0-SNAPSHOTPU</persistence-unit-name>
</persistence-unit-ref>
</web-app>
更新2 :根据要求,这是我的REST外观:
package com.project.moxyws.service;
import com.project.moxyws.UserView;
import com.project.moxyws.controller.UserViewJPAController;
import javax.naming.NamingException;
import javax.persistence.EntityManagerFactory;
import javax.persistence.Persistence;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.WebApplicationException;
@Path("request")
public class UserViewRESTFacade {
private EntityManagerFactory getEntityManagerFactory() throws NamingException {
return (EntityManagerFactory) Persistence
.createEntityManagerFactory("moxyWS_war_1.0-SNAPSHOTPU");
}
private UserViewJPAController getJpaController() {
try {
return new UserViewJPAController(getEntityManagerFactory());
} catch (NamingException ex) {
throw new RuntimeException(ex);
}
}
public UserViewRESTFacade() {
}
@GET
@Path("{client}/{id}")
@Produces({"application/xml", "application/json"})
public UserView findUserByClientAndID(@PathParam("client") String client, @PathParam("id") String id) {
try {
return getJpaController().findUserId(id, client);
} catch (Exception e) {
throw new WebApplicationException(204);
}
}
}
答案 0 :(得分:1)
我认为问题是你的UserRoleList类,它是一个具有单个字段的类,你真的想要映射到一个简单类型。您可能想尝试使用userRoleSID
注释注释@XmlValue
成员。
答案 1 :(得分:1)
使用JAXB映射JPA实体时,我建议使用默认访问(或XmlAccessType.PROPERTY)并注释get方法。 JPA impls有一些技巧来处理延迟加载这样的事情,当使用字段访问时有时会导致问题。
答案 2 :(得分:0)
我无法确定一个答案,但他们全部共同给了我开始检查我的SQL onstructs的想法。事实证明,我的UserRoleList
班级正在采用int
的数据类型。在围栏的另一侧,我的ResultList
是BigDecimal
数据类型的列表。
为了消除任何歧义,我修改了我的SQL语句,将值返回为VARCHAR
,将其作为String
数据类型对象。我更新了我的UserRoleList
类来代表String
个对象,现在一切正常。
我将重新审视我的代码以反映数据类型的正确绑定,但是现在,这让我超越了驼峰,所以我可以完成我的解决方案的原型设计。非常感谢所有人,尤其是 DMoses ,以便快速高效地进行头脑风暴会议。