Question

如果在我的程序中使用scanner.NextDouble（）并且用户输入的内容不是双重的，即任何类型的字符，我如何重新提示它们输入有效的双？我尝试抛出异常并捕获它，但我所做的只是告诉他们这是错误的，我不知道如何将控制权转回try块。如果有人有任何意见，将不胜感激！

private double requestDoubleFromUser( String prompt )
{
    /*** Local Variables ***/

    Scanner sc = new Scanner( System.in );
    double userInput = 0;

    try
    {
    /*** Get input from user ***/

    System.out.print( prompt );
    userInput = sc.nextDouble();
    }

    catch( Exception e )
    {
        System.out.println("That was not a double");
    }

    return userInput;
}

感谢

Answer 1

您可以使用while循环，如下所示：

double userInput = 0;
boolean done = false;
while (!done) {
    try {
        /*** Get input from user ***/
        System.out.print( prompt );
        userInput = sc.nextDouble();
        done = true;
    } catch( Exception e ) {
        System.out.println("That was not a double");
    }
}

Answer 2

您可以将呼叫置于循环中Scanner#nextDouble，并通过捕获InputMismatchException来使用非数字类型。使用Double类型允许循环继续检查输入值。

Scanner sc = new Scanner(System.in);
Double userInput = null;

while (userInput == null) {
    try {
        System.out.print("Enter double:");
        userInput = sc.nextDouble();
    } catch (InputMismatchException e) {
        System.out.println("That was not a double: " + sc.nextLine());
    }
}

Java请求双倍

2 个答案: