Question

所以我有这段代码：

if ((uplImage.FileName != ""))
{
    byte[] raw = new byte[10000];

    //to allow only jpg gif and png files to be uploaded.
    string extension = Path.GetExtension(uplImage.PostedFile.FileName.ToUpper());
    if (((extension == ".JPG") || ((extension == ".GIF") || (extension == ".PNG"))))
    {

        DALBio bio = new DALBio();

        FileStream fs = new FileStream(uplImage.PostedFile.FileName, FileMode.OpenOrCreate, FileAccess.ReadWrite, FileShare.Read);
        fs.Read(raw, 0, System.Convert.ToInt32(fs.Length));

        bio.PlayerID = Session["playerID"].ToString();
        bio.Pending = 'Y';
        bio.Photo = raw;
        DALBio.insertImage(bio);
    }
}

当我尝试这个时，流不会读取图像。 raw永远无法获得图像。它保持为空并且在执行存储过程时被捕获，说我从未传递过图像。我相信代码很好。我不知道为什么我不能将图像放入我的字节数组中。

Answer 1

我做的是获得ByteArray：

public Byte[] GetArrayFromFile(string path)
{
  Byte[] data = null

  FileInfo fileInf = new FileInfo(path);
  long numBytes = fileInf.Length;

  FileStream fStream = nw FileStream(path, FileMode.Open, FileAccess.Read);

  BinaryReader bReader = new BinaryReader(fStream);

  data = bReader.ReadBytes((int)numBytes);
  return data;
}

然后它使用Entity Framework正确地存储在数据库中（如果您的DAL在数据库中正确插入对象，它应该可以正常工作。）

Answer 2

您可以将raw数组创建/定义为

     FileStream fs = new FileStream(uplImage.PostedFile.FileName, 
                         FileMode.OpenOrCreate, FileAccess.ReadWrite, 
                          FileShare.Read);

    raw = new byte[fs.Length]; 

// same code as above..

您也可以尝试类似的代码

        System.IO.Stream myStream;
        Int32 fileLen;

        // Get the length of the file.
        fileLen = uplImage.PostedFile.ContentLength;  


        // Create a byte array to hold the contents of the file.
        Byte[] input = new Byte[fileLen];

        // Initialize the stream to read the uploaded file.
        myStream = uplImage.FileContent;

        // Read the file into the byte array.
        myStream.Read(input, 0, fileLen); 
        // input will hold the byte array

将图像插入数据库c＃

2 个答案: