我有这种并行高斯消元码。调用MPI_Gather
函数调用时会发生分段错误。我知道如果没有为任何缓冲区正确分配内存,这样的错误可能会增加。但我看不出内存管理代码有任何问题。
有人可以帮忙吗?
感谢。
备注:
该程序从名为.txt
的同一目录中的input.txt
文件中读取。
代码:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include "mpi.h"
/*void print2dAddresses(double** array2d, int rows, int cols)
{
int i;
for(i = 0; i < rows; i++)
{
int j;
for(j = 0; j < cols; j++)
{
printf("%d ", &(array2d[i][j]));
}
printf("\n");
}
printf("------------------------------------");
}*/
double** newMatrix(int rows, int cols)
{
double *data = (double*) malloc(rows * cols * sizeof(double));
double **array= (double **)malloc(rows * sizeof(double*));
int i;
for (i=0; i<rows; i++)
array[i] = &(data[cols*i]);
return array;
}
void freeMatrix(double** mat)
{
free(mat[0]);
free(mat);
}
double** new2dArray(int nrows, int ncols)
{
int i;
double** array2d;
array2d = (double**) malloc(nrows * sizeof(double*));
for(i = 0; i < nrows; i++)
{
array2d[i] = (double*) malloc(ncols * sizeof(double));
}
return array2d;
}
double* new1dArray(int size)
{
return (double*) malloc(size * sizeof(double));
}
void free2dArray(double** array2d, int nrows)
{
int i;
for(i = 0; i < nrows; i++)
{
free(array2d[i]);
}
free(array2d);
}
void print2dArray(double** array2d, int nrows, int ncols)
{
int i, j;
for(i = 0; i < nrows; i++)
{
for(j = 0; j < ncols; j++)
{
printf("%lf ", array2d[i][j]);
}
printf("\n");
}
printf("----------------------\n");
}
void print1dArray(double* array, int size)
{
int i;
for(i = 0; i < size; i++)
{
printf("%lf\n", array[i]);
}
printf("----------------------\n");
}
void read2dArray(FILE* fp, double** array2d, int nrows, int ncols)
{
int i, j;
for(i = 0; i < nrows; i++)
{
for(j = 0; j < ncols; j++)
{
fscanf(fp, "%lf", &(array2d[i][j]));
}
}
}
void read1dArray(FILE* fp, double* array, int size)
{
int i;
for(i = 0; i < size; i++)
{
fscanf(fp, "%lf", &(array[i]));
}
}
void readSymbols(char* symbols, int size, FILE* fp)
{
int i;
for(i = 0; i < size; i++)
{
char c = '\n';
while(c == '\n' | c == ' ' | c == '\t' | c == '\r')
fscanf(fp, "%c", &c);
symbols[i] = c;
}
}
void printSolution(char* symbols, double* x, int size)
{
int i;
for(i = 0; i < size; i++)
{
printf("%c = %lf\n", symbols[i], x[i]);
}
}
double* copy_1d_array(double* original, int size)
{
double* copy_version;
int i;
copy_version = (double*) malloc(size * sizeof(double));
for(i = 0; i < size; i++)
{
copy_version[i] = original[i];
}
return copy_version;
}
int main(int argc, char** argv)
{
int p, rank, i, j, k, l, msize, rowsPerProcess, remainder, startingRow, dest, rowCounter, remainingRows, neededProcesses;
double **A, *b, *x, **smallA, *currentRow, *smallB, currentB, **receivedA, *receivedB;
char *symbols;
MPI_Status status;
MPI_Init(&argc, &argv);
MPI_Comm_size(MPI_COMM_WORLD, &p);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
if(rank == 0)
{
FILE* fp;
fp = fopen("input.txt", "r");
fscanf(fp, "%d", &msize);
A = newMatrix(msize, msize);
b = new1dArray(msize);
x = new1dArray(msize);
symbols = (char*) malloc(msize * sizeof(char));
read2dArray(fp, A, msize, msize);
read1dArray(fp, b, msize);
readSymbols(symbols, msize, fp);
fclose(fp);
/*print2dArray(A, msize, msize);
print1dArray(b, msize);*/
}
MPI_Bcast(&msize, 1, MPI_INT, 0, MPI_COMM_WORLD);
for(i = 0; i < (msize - 1); i++)
{
int maxIndex;
double maxCoef, tmp, r;
/*finding max row*/
if(rank == 0)
{
maxIndex = i;
maxCoef = fabs(A[i][i]);
for(j = i + 1; j < msize; j++)
{
if(fabs(A[j][i]) > maxCoef)
{
maxCoef = A[j][i];
maxIndex = j;
}
}
/*swapping the current row with the max row*/
for(j = 0; j < msize; j++)
{
tmp = A[i][j];
A[i][j] = A[maxIndex][j];
A[maxIndex][j] = tmp;
}
tmp = b[i];
b[i] = b[maxIndex];
b[maxIndex] = tmp;
/*elimination*/
/*for(j = i + 1; j < msize; j++)
{
double r = A[j][i] / A[i][i];
subtracting r * row i from row j
for(k = i; k < msize; k++)
{
A[j][k] -= r * A[i][k];
}
b[j] -= r * b[i];
}*/
/*parallel elimination*/
startingRow = i + 1;
neededProcesses = p;
remainingRows = msize - startingRow;
if(remainingRows < neededProcesses)
{
neededProcesses = remainingRows;
}
rowsPerProcess = remainingRows / neededProcesses;
remainder = remainingRows % neededProcesses;
}
MPI_Bcast(&startingRow, 1, MPI_INT, 0, MPI_COMM_WORLD);
MPI_Bcast(&rowsPerProcess, 1, MPI_INT, 0, MPI_COMM_WORLD);
if(rank == 0)
{
currentRow = copy_1d_array(A[startingRow-1], msize);
currentB = b[startingRow-1];
}
else
{
currentRow = new1dArray(msize);
}
MPI_Bcast(currentRow, msize, MPI_DOUBLE, 0, MPI_COMM_WORLD);
MPI_Bcast(¤tB, 1, MPI_DOUBLE, 0, MPI_COMM_WORLD);
if(rank == 0)
{
receivedA = newMatrix(remainingRows, msize);
receivedB = new1dArray(remainingRows);
}
smallA = newMatrix(rowsPerProcess, msize);
smallB = new1dArray(rowsPerProcess);
MPI_Scatter(&(A[startingRow][0]), rowsPerProcess*msize, MPI_DOUBLE, &(smallA[0][0]), rowsPerProcess*msize, MPI_DOUBLE, 0, MPI_COMM_WORLD);
MPI_Scatter(&(b[startingRow]), rowsPerProcess, MPI_DOUBLE, &(smallB[0]), rowsPerProcess, MPI_DOUBLE, 0, MPI_COMM_WORLD);
for(j = 0; j < rowsPerProcess; j++)
{
r = smallA[j][startingRow-1] / currentRow[startingRow-1];
for(k = 0; k < msize; k++)
{
smallA[j][k] -= r * currentRow[k];
}
smallB[j] -= r * currentB;
}
MPI_Gather(&(smallA[0][0]), rowsPerProcess*msize, MPI_DOUBLE, &(receivedA[0][0]), rowsPerProcess*msize, MPI_DOUBLE, 0, MPI_COMM_WORLD);
MPI_Gather(&(smallB[0]), rowsPerProcess, MPI_DOUBLE, &(receivedB[0]), rowsPerProcess, MPI_DOUBLE, 0, MPI_COMM_WORLD);
freeMatrix(smallA);
free(smallB);
if(rank == 0)
{
for(j = 0; j < remainingRows; j++)
{
for(k = 0; k < msize; k++)
{
A[j+startingRow][k] = receivedA[j][k];
}
b[j+startingRow] = receivedB[j];
}
free(currentRow);
freeMatrix(receivedA);
free(receivedB);
}
if(rank == 0)
{
if(remainder > 0)
{
for(j = (msize - remainder); j < msize; j++)
{
r = A[j][i] / A[i][i];
for(k = 0; k < msize; k++)
{
A[j][k] -= r * A[i][k];
}
b[j] -= r * b[i];
}
}
}
}
if(rank == 0)
{
/*backward substitution*/
for(i = msize - 1; i >= 0; i--)
{
x[i] = b[i];
for(j = msize - 1; j > i; j--)
{
x[i] -= A[i][j] * x[j];
}
x[i] /= A[i][i];
}
printf("solution = \n");
//print1dArray(x, msize);
printSolution(symbols, x, msize);
freeMatrix(A);
free(b);
free(x);
free(symbols);
}
MPI_Finalize();
return 0;
}
输入文件:
3
1 1 1
1 1 3
2 1 4
4
9
12
x
y
z
答案 0 :(得分:2)
可能是:&(receivedA[0][0])
处理rank != 0
的进程。您正在索引尚未分配的数组。您可能需要创建另一个指针,如下所示:
if(rank == 0)
{
receivedA = newMatrix(remainingRows, msize);
recievedAHead = &(receivedA[0][0]);
receivedB = new1dArray(remainingRows);
}
else {
recievedAHead = NULL;
}
并在MPI_Gather调用中使用recievedAHead
。