我读了这篇code(由Bjarne Stroustrup撰写)。我很困惑...... main
函数体不在{}
中,函数不返回值(如int
)。它有效......为什么?
#include "std_lib_facilities.h"
int main()
try
{
cout<< "please enter two floating-point values separated by an operator\n The operator can be + - * or / : ";
double val1 = 0;
double val2 = 0;
char op = 0;
while (cin>>val1>>op>>val2) { // read number operation number
string oper;
double result;
switch (op) {
case '+':
oper = "sum of ";
result = val1+val2;
break;
case '-':
oper = "difference between ";
result = val1-val2;
break;
case '*':
oper = "product of ";
result = val1*val2;
break;
case '/':
oper = "ratio of";
if (val2==0) error("trying to divide by zero");
result = val1/val2;
break;
//case '%':
// oper = "remainder of ";
// result = val1%val2;
// break;
default:
error("bad operator");
}
cout << oper << val1 << " and " << val2 << " is " << result << '\n';
cout << "Try again: ";
}
}
catch (runtime_error e) { // this code is to produce error messages; it will be described in Chapter 5
cout << e.what() << '\n';
keep_window_open("~"); // For some Windows(tm) setups
}
catch (...) { // this code is to produce error messages; it will be described in Chapter 5
cout << "exiting\n";
keep_window_open("~"); // For some Windows(tm) setups
}
答案 0 :(得分:6)
该代码使用Function Try Block,这是一种特殊语法,允许将函数的整个主体嵌入到try / catch块中(主要用于类构造函数,以便捕获构造函数抛出的异常)基础或成员子对象)。
此外,main()
是唯一的值返回函数,不需要显式返回值。如果未指定返回值,则假定为0
。
根据C ++ 11标准的第3.6.1 / 5段:
main
中的return语句具有离开main
函数的效果(使用自动销毁任何对象) 存储持续时间)并以返回值作为参数调用std::exit
。如果控制到达终点main
没有遇到return语句,效果就是执行return 0;