Question

我有以下代码，我希望更改/重命名上传到用户ID的图像名称，这样我就可以避免文件覆盖，并在添加重命名代码后代码无法上传图像或者将名称插入数据库更新数据库，我们显示任何错误，但如果我删除重命名代码一切正常。可以帮助我如何解决它，还是有更好的方法可以解决它？

<?php
$user_id = htmlentities($_SESSION['user']['id'], ENT_QUOTES, 'UTF-8');
$username = htmlentities($_SESSION['user']['username'], ENT_QUOTES, 'UTF-8');
require("connection.php");
if(@$_POST ['submit']) {
    $file = $_FILES ['file'];
    $name1 = $file ['name'];
    $type = $file ['type'];
    $size = $file ['size'];
    $tmppath = $file ['tmp_name'];
    if($type == 'jpeg' || $type == 'png' || $type == 'jpg') {
        $name1 = $user_id.$type; // rename image
        if($name1!="") {
            if(move_uploaded_file ($tmppath, 'users/'.$name1)) {
                $sql=("INSERT INTO USERS set photo='$name1' WHERE username='$username'");
                mysql_query ($sql) or die ('could not updated:'.mysql_error());
                echo ("Profile picture updated");
            }
        }
    } 
}
?>

Answer 1

你可以尝试一下，可能会帮助你...

<?php
$user_id = htmlentities($_SESSION['user']['id'], ENT_QUOTES, 'UTF-8');
$username = htmlentities($_SESSION['user']['username'], ENT_QUOTES, 'UTF-8');
require("connection.php");
if(@$_POST ['submit']) {
$file = $_FILES ['file'];
$name1 = time().$file ['name']; // rename image
$type = $file ['type'];
$size = $file ['size'];
$tmppath = $file ['tmp_name'];
if($type == 'image/jpeg' || $type == 'image/png' || $type == 'image/jpg') {
    if($name1!="") {
        if(move_uploaded_file ($tmppath, 'users/'.$name1)) {
            $sql=("INSERT INTO USERS set photo='$name1' WHERE username='$username'");
            mysql_query ($sql) or die ('could not updated:'.mysql_error());
            echo ("Profile picture updated");
        }
    }
} 
}}
?>

Answer 2

首先改变 $name1 = $user_id.$type;

到

$name1 = $user_id.".".$type; 第二个是清理你的SQL。

另外。 file_type是image / jpeg，这就是为什么它不起作用。它永远不会超过你的if。

创建一个开关来检查文件类型或只记录文件的最后3个字符。

Answer 3

尝试将$_FILES重组为您可以理解并轻松使用的数组。

无耻插件

https://gist.github.com/lukeoliff/5531772#file-quickrearrangefiles-php

<?php
  function rearrangeFiles($arr) {
    foreach($arr as $key => $all){
      foreach($all as $i => $val){
        $new[$i][$key] = $val;
      }
    }
    return $new;
  }

原样使用：

<?php
  $user_id = htmlentities($_SESSION['user']['id'], ENT_QUOTES, 'UTF-8');
  $username = htmlentities($_SESSION['user']['username'], ENT_QUOTES, 'UTF-8');

  require("connection.php");

  if(!empty($_POST) && !empty($_FILES)) {
    $files = rearrangeFiles($_FILES)
    foreach ($files as $key => $file) {
      $name    = $file['name'];
      $type    = $file['type'];
      $size    = $file['size'];
      $tmppath = $file['tmp_name'];
      if($type == 'jpeg' || $type == 'png' || $type == 'jpg') {
        $name = time() . '_' . $user_id.'_'.$name.'.'.$type; // TIMESTAMP, USERID and FILENAME RENAME
        if(!empty($name)) {
          if(move_uploaded_file($tmppath, 'users/'.$name)) {
            $sql = "INSERT INTO users (photo,username) values ('$name','$username')";
            mysql_query($sql) or die('could not updated:'.mysql_error());
            $successes[] = $file['name'] . " picture saved as " . $name;
          }
        }
      } 
    }
    if (!empty($successes)) {
      echo implode('. ',$successes);
    }
  }

通过在单个查询中插入数据库进一步改进:)另外你真的需要从mysql_函数移动到mysqli_或PDO ::函数，因为php.net http://www.php.net/manual/en/function.mysql-connect.php很快就会贬低mysql_函数。

Answer 4

您可以使用这一个概念，但可以根据您的要求进行编辑。

<?php
if ($_FILES['imagepath']['name'] != "")
{
    $uploaddir = 'images/';
    $uploadfile = $uploaddir . basename($_FILES['imagepath']['name']);
    if (move_uploaded_file($_FILES['imagepath']['tmp_name'], $uploadfile))
    {
    $rename = $_FILES['imagepath']['name'];
                $rename = rand(0,1500000000).$rename;
                $filename = strtolower(($rename));
                if (file_exists(($uploaddir.$_FILES['imagepath']['name'])))
                    rename(($uploaddir.$_FILES['imagepath']['name']), ($uploaddir.$filename));
    echo $_FILES['imagepath']['name']."&nbsp;with name&nbsp;".$filename."&nbsp;file uploaded successfully";
    }
}
?>

上传期间重命名图像不能使用Mysql设置

4 个答案: