Question

我正在使用Mule Community Edition 3.4。我有一个UntilSuccessful组件的问题。该方案现已公开：我有一个由UntilSuccessful组件组成的流，其中有一个SOAP组件向Web服务发出请求。在这个流程中也有一个ExcpetionStrategy。我遇到的问题是，当在UntilSuccessful内部发生异常时（即在SOAP组件中），ExcpetionStrategy无法处理它，因为它（抛出异常）由UntilSuccessful组件内的某些机制处理。因为我需要在ExcpetionStrategy中处理Exception，所以我想构建一个自定义的出站拦截器（在SOAP组件内）拦截SOAP响应（抛出异常）并且能够抛出异常以触发ExcpetionStrategy。任何人都可以帮我解决这个问题吗？我试图阅读文档，但它很稀疏，并没有很好地解释如何构建自定义出站异常。我要做的是保存抛出Exception的名称（即如果服务器抛出NumberFormatException，我会将其名称保存在某处以便在ExceptionStrategy中使用它）

下面你可以看到一个mule配置文件片段：

<flow name="ProvaClient" doc:name="ProvaClient">
        <quartz:inbound-endpoint jobName="TalendJob" repeatInterval="5000" repeatCount="0" responseTimeout="10000" doc:name="Quartz">
            <quartz:event-generator-job>
                <quartz:payload>error</quartz:payload>
            </quartz:event-generator-job>
        </quartz:inbound-endpoint>
        <object-to-string-transformer doc:name="Object to String"/>
        <until-successful objectStore-ref="OS_Bean" maxRetries="2" secondsBetweenRetries="2" doc:name="Until Successful" deadLetterQueue-ref="myQueue">
            <processor-chain doc:name="Processor Chain: Wait For Web Service Response">
                <processor-chain doc:name="Processor Chain: Web Service">
                    <cxf:jaxws-client operation="getCode" clientClass="it.aizoon.prova.client.ProvaService" port="ProvaPort" enableMuleSoapHeaders="true" doc:name="SOAP">
                    </cxf:jaxws-client>
                      <http:outbound-endpoint exchange-pattern="request-response" host="localhost" port="8081" path="service/prova" method="POST" doc:name="HTTP"/>
                </processor-chain>
                <logger message="PAYLOAD: #[payload]" level="INFO" doc:name="Logger"/>
            </processor-chain>
        </until-successful>
        <catch-exception-strategy doc:name="Catch Exception Strategy">
           <!--   <processor ref="myExceptionHandler_id"/>  -->
            <logger message="EXCEPTION STRATEGY" level="INFO" doc:name="Logger"/>
        </catch-exception-strategy>
</flow>

在这里，您可以看到公开Web服务的服务器：

<flow name="provaServer" doc:name="provaServer">
        <http:inbound-endpoint exchange-pattern="request-response" doc:name="HTTP" host="localhost" path="service/prova" port="8081"/>
        <logger message="SERVER" level="INFO" doc:name="Logger"/>
        <cxf:jaxws-service serviceClass="it.aizoon.prova.Prova" doc:name="Process SOAP Request" />
        <component class="it.aizoon.prova.ProvaImpl" doc:name="Java"/>
</flow>

这里有ProvaImpl.java，即Web Service的实现。你怎么看，如果在getCode（）函数中作为参数传递的字符串是错误的，抛出异常，我会认为它是由客户端中定义的异常策略管理的

@WebService(endpointInterface = "it.aizoon.prova.Prova",
                  serviceName = "Prova")
public class ProvaImpl implements Prova{

      @Override
      public String getCode(String code) throws NumberFormatException{
            // TODO Auto-generated method stub
            if(code.equals("error"))    throw new NumberFormatException();

            String str = "Andato a buon fine!";
            return str;
      }
}

Answer 1

我会改变方法，而不是使用拦截器。如果你需要调用异常策略而不首先触发直到成功的路由器，我会将你的cxf：jaxws-client等移动到私有流。引用Mule in Action第2版关于私人流程：

这种解耦允许定义处理和错误处理私人流程的本地策略。

<flow name="ProvaClient" doc:name="ProvaClient">
    ...
    <until-successful objectStore-ref="OS_Bean"
        maxRetries="2" secondsBetweenRetries="2" doc:name="Until Successful"
        deadLetterQueue-ref="myQueue">
        <processor-chain doc:name="Processor Chain: Wait For Web Service Response">
            <processor-chain doc:name="Processor Chain: Web Service">
                <flow-ref name="externalCallFlow" />
            </processor-chain>
            <logger message="PAYLOAD: #[payload]" level="INFO" doc:name="Logger" />
        </processor-chain>
    </until-successful>

    ...
</flow>
<flow name="externalCallFlow">
    <cxf:jaxws-client operation="getCode"
        clientClass="it.aizoon.prova.client.ProvaService" port="ProvaPort"
        enableMuleSoapHeaders="true" doc:name="SOAP">
    </cxf:jaxws-client>
    <http:outbound-endpoint exchange-pattern="request-response"
        host="localhost" port="8081" path="service/prova" method="POST"
        doc:name="HTTP" />
    <catch-exception-strategy doc:name="Catch Exception Strategy">
        <!-- Handle exception here locally and return custom exception or error 
            message for the unil-successful router -->
    </catch-exception-strategy>
</flow>

然后，您可以在本地处理异常并返回自定义异常或错误使用以下属性捕获直到成功的路由器的消息：failureExpression =“exception-type：java.lang.NumberFormatException”

这是一个虚拟示例，我敲了一下抛出一个NumberFormatException，在异常策略中记录异常并重试：

<flow name="test" doc:name="test">
        <http:inbound-endpoint address="http://localhost:8081/test"
            doc:name="HTTP" />

        <until-successful objectStore-ref="OS_Bean"
            maxRetries="2" secondsBetweenRetries="2" doc:name="Until Successful">
            <processor-chain doc:name="Processor Chain: Wait For Web Service Response">
                <processor-chain doc:name="Processor Chain: Web Service">
                    <flow-ref name="externalCallFlow" doc:name="Flow Reference" />
                </processor-chain>
            </processor-chain>
        </until-successful>

    </flow>
    <flow name="externalCallFlow" doc:name="externalCallFlow">
        <scripting:component>
            <scripting:script engine="groovy">
                throw new java.lang.NumberFormatException();
                </scripting:script>
        </scripting:component>
        <default-exception-strategy>
            <processor-chain>
                <logger level="ERROR"
                    message="NumberFormatException Occurred : #[message.payload.getException().getCause()]" />
                <scripting:component>
                    <scripting:script engine="groovy">
                        throw message.payload.getException().getCause();
                </scripting:script>
                </scripting:component>
            </processor-chain>
        </default-exception-strategy>
    </flow>

使用SOAP Web服务MULE构建自定义拦截器

1 个答案: