我需要帮助在Oracle中编写查询以获取以下数据。数据按人员和日期字段排序。
Person Day Flag
------ --- ----
person1 day1 Y
person1 day2 Y
person1 day3 Y
person1 day4 N
person1 day5 N
person1 day6 Y
person1 day7 Y
person1 day8 Y
我需要有一个Group_Number列，只要Flag值发生变化就会增加。我的结果应如下所示
Person Day Flag Group_Number
------ --- ---- ------------
person1 day1 Y 1
person1 day2 Y 1
person1 day3 Y 1
person1 day4 N 2
person1 day5 N 2
person1 day6 Y 3
person1 day7 Y 3
person1 day8 Y 3
我认为有办法使用ROW_NUMBER，LEAD等分析函数获得上述结果。
答案 0 :(得分：15)
您可以合并analytic functions SUM（用作总计）和LAG：
SQL> WITH data AS (
2 SELECT 'person1' person, 'day1' day, 'Y' flag FROM dual
3 UNION ALL SELECT 'person1' person, 'day2' day, 'Y' flag FROM dual
4 UNION ALL SELECT 'person1' person, 'day3' day, 'Y' flag FROM dual
5 UNION ALL SELECT 'person1' person, 'day4' day, 'N' flag FROM dual
6 UNION ALL SELECT 'person1' person, 'day5' day, 'N' flag FROM dual
7 UNION ALL SELECT 'person1' person, 'day6' day, 'Y' flag FROM dual
8 UNION ALL SELECT 'person1' person, 'day7' day, 'Y' flag FROM dual
9 UNION ALL SELECT 'person1' person, 'day8' day, 'Y' flag FROM dual
10 )
11 SELECT person, DAY, flag, SUM(gap) over (PARTITION BY person
12 ORDER BY DAY) grp
13 FROM (SELECT person, DAY, flag,
14 CASE WHEN flag = lag(flag) over (PARTITION BY person
15 ORDER BY DAY)
16 THEN 0
17 ELSE 1
18 END gap
19 FROM DATA);
PERSON DAY FLAG GRP
------- ---- ---- ----------
person1 day1 Y 1
person1 day2 Y 1
person1 day3 Y 1
person1 day4 N 2
person1 day5 N 2
person1 day6 Y 3
person1 day7 Y 3
person1 day8 Y 3