Question

我使用以下查询按记录选择分组。

SELECT  YEARWEEK(dtentered) week, sum(leftcount) as lct, sum(rightcount) as rct FROM `dailycount` WHERE paid='1'  and regid='SF00033200712' GROUP BY YEARWEEK(dtentered) "

但我只收到当前的周报。我想显示所有每周报告。我不知道如何改变它。

CREATE TABLE IF NOT EXISTS `dailycount` (
    `countid` int(11) NOT NULL AUTO_INCREMENT,
    `regid` varchar(13) NOT NULL,
    `paid` int(11) NOT NULL,
    `dtentered` date NOT NULL,
    `leftcount` int(11) NOT NULL,
    `rightcount` int(11) NOT NULL,
    `carryleft` int(11) NOT NULL,
    `carryright` int(11) NOT NULL,
    `total_pairs` int(11) NOT NULL,
    `gross` int(11) NOT NULL,
    `service` decimal(19,2) NOT NULL DEFAULT '0.00',
    `net` decimal(19,2) NOT NULL DEFAULT '0.00',
    PRIMARY KEY (`countid`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1 AUTO_INCREMENT=33 ;


INSERT INTO `dailycount` (`countid`, `regid`, `paid`, `dtentered`, `leftcount`, `rightcount`, `carryleft`, `carryright`, `total_pairs`, `gross`, `service`, `net`) VALUES
    (6, 'SF00033200712', 1, '2013-05-14', 0, 1, 0, 0, 0, 0, 0.00, 0.00),
    (5, 'SF00034140513', 1, '2013-05-14', 0, 1, 0, 0, 0, 0, 0.00, 0.00),
    (4, 'SF00033200712', 1, '2013-05-14', 0, 1, 0, 0, 0, 0, 0.00, 0.00),
    (7, 'SF00035140513', 1, '2013-05-14', 0, 1, 0, 0, 0, 0, 0.00, 0.00),
    (8, 'SF00034140513', 1, '2013-05-14', 0, 1, 0, 0, 0, 0, 0.00, 0.00),
    (9, 'SF00033200712', 1, '2013-05-14', 0, 1, 0, 0, 0, 0, 0.00, 0.00),
    (10, 'SF00033200712', 1, '2013-05-14', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (11, 'SF00034140513', 1, '2013-05-14', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (12, 'SF00033200712', 1, '2013-05-14', 0, 1, 0, 0, 0, 0, 0.00, 0.00),
    (13, 'SF00037140513', 1, '2013-05-14', 0, 1, 0, 0, 0, 0, 0.00, 0.00),
    (14, 'SF00033200712', 1, '2013-05-14', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (15, 'SF00039140513', 1, '2013-05-14', 0, 1, 0, 0, 0, 0, 0.00, 0.00),
    (16, 'SF00037140513', 1, '2013-05-14', 0, 1, 0, 0, 0, 0, 0.00, 0.00),
    (17, 'SF00033200712', 1, '2013-05-14', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (18, 'SF00037140513', 1, '2013-05-14', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (19, 'SF00033200712', 1, '2013-05-14', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (20, 'SF00041140513', 1, '2013-05-14', 0, 1, 0, 0, 0, 0, 0.00, 0.00),
    (21, 'SF00037140513', 1, '2013-05-14', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (22, 'SF00033200712', 1, '2013-05-14', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (23, 'SF00039140513', 1, '2013-05-14', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (24, 'SF00037140513', 1, '2013-05-14', 0, 1, 0, 0, 0, 0, 0.00, 0.00),
    (25, 'SF00033200712', 1, '2013-05-14', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (26, 'SF00041140513', 1, '2013-05-22', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (27, 'SF00037140513', 1, '2013-05-22', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (28, 'SF00033200712', 1, '2013-05-22', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (29, 'SF00042140513', 1, '2013-05-15', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (30, 'SF00041140513', 1, '2013-05-15', 0, 1, 0, 0, 0, 0, 0.00, 0.00),
    (31, 'SF00037140513', 1, '2013-05-15', 1, 0, 0, 0, 0, 0, 0.00, 0.00),
    (32, 'SF00033200712', 1, '2013-05-15', 1, 0, 0, 0, 0, 0, 0.00, 0.00);

Answer 1

查询：

<强> SQLFIDDLEExample

SELECT  YEARWEEK(dtentered) week,
        sum(leftcount) as lct,
        sum(rightcount) as rct 
FROM `dailycount` 
WHERE paid='1'  and regid='SF00033200712'
GROUP BY YEARWEEK(dtentered)

结果：

|   WEEK | LCT | RCT |
----------------------
| 201319 |   7 |   4 |
| 201320 |   1 |   0 |

查询：

<强> SQLFIDDLEExample

SELECT  WEEK(dtentered) week,
        sum(leftcount) as lct,
        sum(rightcount) as rct,
 CONCAT(DATE_FORMAT(DATE_ADD(dtentered, INTERVAL(1-DAYOFWEEK(dtentered)) DAY),'%Y-%m-%e'), ' TO ',    
 DATE_FORMAT(DATE_ADD(dtentered, INTERVAL(7-DAYOFWEEK(dtentered)) DAY),'%Y-%m-%e')) AS DateRange
FROM `dailycount` 
WHERE paid='1'  and regid='SF00033200712'
GROUP BY YEARWEEK(dtentered)

结果：

| WEEK | LCT | RCT |                DATERANGE |
-----------------------------------------------
|   19 |   7 |   4 | 2013-05-12 TO 2013-05-18 |
|   20 |   1 |   0 | 2013-05-19 TO 2013-05-25 |

按周报告选择“从SQL组查询”

1 个答案: