JavaScript中最快的MD5实现

时间:2009-10-31 22:15:51

标签: javascript performance md5

有许多MD5 JavaScript实现。 有谁知道哪一个是最先进的,最错误的,最快的?

我需要this工具。

18 个答案:

答案 0 :(得分:154)

我听说约瑟夫的迈尔斯实施得非常快。此外,他在Javascript优化方面有一个lengthy article,描述了他在编写实现时学到了什么。对于对高性能javascript感兴趣的人来说,这是一个很好的阅读。

http://www.webreference.com/programming/javascript/jkm3/

可以找到他的MD5实施here

答案 1 :(得分:63)

我建议你在这种情况下使用CryptoJS。

基本上,CryptoJS是使用最佳实践和模式在JavaScript中实现的标准和安全加密算法的不断增长的集合。它们很快,并且具有一致且简单的界面。

因此,如果要计算密码字符串的MD5哈希值,请执行以下操作:

<script src="https://cdnjs.cloudflare.com/ajax/libs/crypto-js/3.1.9-1/md5.js"></script>
<script>
    var passhash = CryptoJS.MD5(password);

    $.post(
      'includes/login.php', 
      { user: username, pass: passhash },
      onLogin, 
      'json' );
</script>

因此,此脚本会将密码字符串的哈希值发布到服务器。

有关其他哈希计算算法的更多信息和支持,您可以访问:

http://code.google.com/p/crypto-js/

答案 2 :(得分:25)

在选择库时,同样重要的是看它是否支持现代框架,如Bower,传递jslint,支持JQuery的插件模型或模块系统(如AMD / RequireJS)以及正在进行的活动,并且拥有1个以上的贡献者。有几个选项可以满足部分或全部这些附加标准:

  • CryptoJS:这可能是最具扩展性的库,每个算法可以单独使用,而不会在JS代码中添加任何内容。加上它作为UTF8,UTF16和Base64的编码器/解码器。我保留了注册为Bower包的github repository以及如何将其与RequireJS一起使用的说明。
  • Spark MD5:这是基于JKM代码,其他答案提到哪些也是更快的实现。但是另外,Spark实现增加了AMD支持,传递jslint plus有增量模式。它没有Base64 o / p但它确实有原始的o / p(即32位int insead of string的数组)。
  • JQuery MD5 plugin:脚踏实地非常简单,但似乎没有原始模式。
  • JavaScript-MD5:不像Spark那样花哨或快,但更简单。

来自CryptoJS的示例:

//just include md5.js from the CryptoJS rollups folder
var hash = CryptoJS.MD5("Message");
console.log(hash.toString()); 

http://jsperf.com/md5-shootout/7上面的库之间存在性能比较。在我的机器上,当前的测试(无可否认是旧的)表明,如果你正在寻找速度,Spark MD5是你最好的选择(简单的JKM代码也是如此)。但是如果你想要更全面的库,那么CryptoJS是你最好的选择,虽然它比Spark MD5慢79%。但是我会想象CryptoJS最终会达到相同的速度,因为它是更活跃的项目。

答案 3 :(得分:10)

截至2020年,最快的MD5实现可能是用WASM(Web汇编)编写的。

hash-wasm是一个在WASM中实现MD5哈希的库。

您可以找到基准here

您可以使用npm安装它:

npm i hash-wasm

或仅添加脚本标签

<script src="https://cdn.jsdelivr.net/npm/hash-wasm"></script>

然后使用hashwasm全局变量。

示例:

async function run() {
  console.log('MD5:', await hashwasm.md5('The quick brown fox jumps over the lazy dog'));
}

run();

输出

MD5: 9e107d9d372bb6826bd81d3542a419d6

答案 4 :(得分:10)

我发现了很多关于这个主题的文章。 他们都建议Joseph Meyers的实施。

在某些测试中看到http://jsperf.com/md5-shootout

在我寻求最终速度时,我看了这段代码,我看到它可以改进。所以我根据Joseph Meyers代码创建了一个新的JS脚本。

请参阅Improved Jospeh Meyers code

答案 5 :(得分:10)

MD5 = function(e) {
    function h(a, b) {
        var c, d, e, f, g;
        e = a & 2147483648;
        f = b & 2147483648;
        c = a & 1073741824;
        d = b & 1073741824;
        g = (a & 1073741823) + (b & 1073741823);
        return c & d ? g ^ 2147483648 ^ e ^ f : c | d ? g & 1073741824 ? g ^ 3221225472 ^ e ^ f : g ^ 1073741824 ^ e ^ f : g ^ e ^ f
    }

    function k(a, b, c, d, e, f, g) {
        a = h(a, h(h(b & c | ~b & d, e), g));
        return h(a << f | a >>> 32 - f, b)
    }

    function l(a, b, c, d, e, f, g) {
        a = h(a, h(h(b & d | c & ~d, e), g));
        return h(a << f | a >>> 32 - f, b)
    }

    function m(a, b, d, c, e, f, g) {
        a = h(a, h(h(b ^ d ^ c, e), g));
        return h(a << f | a >>> 32 - f, b)
    }

    function n(a, b, d, c, e, f, g) {
        a = h(a, h(h(d ^ (b | ~c), e), g));
        return h(a << f | a >>> 32 - f, b)
    }

    function p(a) {
        var b = "",
            d = "",
            c;
        for (c = 0; 3 >= c; c++) d = a >>> 8 * c & 255, d = "0" + d.toString(16), b += d.substr(d.length - 2, 2);
        return b
    }
    var f = [],
        q, r, s, t, a, b, c, d;
    e = function(a) {
        a = a.replace(/\r\n/g, "\n");
        for (var b = "", d = 0; d < a.length; d++) {
            var c = a.charCodeAt(d);
            128 > c ? b += String.fromCharCode(c) : (127 < c && 2048 > c ? b += String.fromCharCode(c >> 6 | 192) : (b += String.fromCharCode(c >> 12 | 224), b += String.fromCharCode(c >> 6 & 63 | 128)), b += String.fromCharCode(c & 63 | 128))
        }
        return b
    }(e);
    f = function(b) {
        var a, c = b.length;
        a = c + 8;
        for (var d = 16 * ((a - a % 64) / 64 + 1), e = Array(d - 1), f = 0, g = 0; g < c;) a = (g - g % 4) / 4, f = g % 4 * 8, e[a] |= b.charCodeAt(g) << f, g++;
        a = (g - g % 4) / 4;
        e[a] |= 128 << g % 4 * 8;
        e[d - 2] = c << 3;
        e[d - 1] = c >>> 29;
        return e
    }(e);
    a = 1732584193;
    b = 4023233417;
    c = 2562383102;
    d = 271733878;
    for (e = 0; e < f.length; e += 16) q = a, r = b, s = c, t = d, a = k(a, b, c, d, f[e + 0], 7, 3614090360), d = k(d, a, b, c, f[e + 1], 12, 3905402710), c = k(c, d, a, b, f[e + 2], 17, 606105819), b = k(b, c, d, a, f[e + 3], 22, 3250441966), a = k(a, b, c, d, f[e + 4], 7, 4118548399), d = k(d, a, b, c, f[e + 5], 12, 1200080426), c = k(c, d, a, b, f[e + 6], 17, 2821735955), b = k(b, c, d, a, f[e + 7], 22, 4249261313), a = k(a, b, c, d, f[e + 8], 7, 1770035416), d = k(d, a, b, c, f[e + 9], 12, 2336552879), c = k(c, d, a, b, f[e + 10], 17, 4294925233), b = k(b, c, d, a, f[e + 11], 22, 2304563134), a = k(a, b, c, d, f[e + 12], 7, 1804603682), d = k(d, a, b, c, f[e + 13], 12, 4254626195), c = k(c, d, a, b, f[e + 14], 17, 2792965006), b = k(b, c, d, a, f[e + 15], 22, 1236535329), a = l(a, b, c, d, f[e + 1], 5, 4129170786), d = l(d, a, b, c, f[e + 6], 9, 3225465664), c = l(c, d, a, b, f[e + 11], 14, 643717713), b = l(b, c, d, a, f[e + 0], 20, 3921069994), a = l(a, b, c, d, f[e + 5], 5, 3593408605), d = l(d, a, b, c, f[e + 10], 9, 38016083), c = l(c, d, a, b, f[e + 15], 14, 3634488961), b = l(b, c, d, a, f[e + 4], 20, 3889429448), a = l(a, b, c, d, f[e + 9], 5, 568446438), d = l(d, a, b, c, f[e + 14], 9, 3275163606), c = l(c, d, a, b, f[e + 3], 14, 4107603335), b = l(b, c, d, a, f[e + 8], 20, 1163531501), a = l(a, b, c, d, f[e + 13], 5, 2850285829), d = l(d, a, b, c, f[e + 2], 9, 4243563512), c = l(c, d, a, b, f[e + 7], 14, 1735328473), b = l(b, c, d, a, f[e + 12], 20, 2368359562), a = m(a, b, c, d, f[e + 5], 4, 4294588738), d = m(d, a, b, c, f[e + 8], 11, 2272392833), c = m(c, d, a, b, f[e + 11], 16, 1839030562), b = m(b, c, d, a, f[e + 14], 23, 4259657740), a = m(a, b, c, d, f[e + 1], 4, 2763975236), d = m(d, a, b, c, f[e + 4], 11, 1272893353), c = m(c, d, a, b, f[e + 7], 16, 4139469664), b = m(b, c, d, a, f[e + 10], 23, 3200236656), a = m(a, b, c, d, f[e + 13], 4, 681279174), d = m(d, a, b, c, f[e + 0], 11, 3936430074), c = m(c, d, a, b, f[e + 3], 16, 3572445317), b = m(b, c, d, a, f[e + 6], 23, 76029189), a = m(a, b, c, d, f[e + 9], 4, 3654602809), d = m(d, a, b, c, f[e + 12], 11, 3873151461), c = m(c, d, a, b, f[e + 15], 16, 530742520), b = m(b, c, d, a, f[e + 2], 23, 3299628645), a = n(a, b, c, d, f[e + 0], 6, 4096336452), d = n(d, a, b, c, f[e + 7], 10, 1126891415), c = n(c, d, a, b, f[e + 14], 15, 2878612391), b = n(b, c, d, a, f[e + 5], 21, 4237533241), a = n(a, b, c, d, f[e + 12], 6, 1700485571), d = n(d, a, b, c, f[e + 3], 10, 2399980690), c = n(c, d, a, b, f[e + 10], 15, 4293915773), b = n(b, c, d, a, f[e + 1], 21, 2240044497), a = n(a, b, c, d, f[e + 8], 6, 1873313359), d = n(d, a, b, c, f[e + 15], 10, 4264355552), c = n(c, d, a, b, f[e + 6], 15, 2734768916), b = n(b, c, d, a, f[e + 13], 21, 1309151649), a = n(a, b, c, d, f[e + 4], 6, 4149444226), d = n(d, a, b, c, f[e + 11], 10, 3174756917), c = n(c, d, a, b, f[e + 2], 15, 718787259), b = n(b, c, d, a, f[e + 9], 21, 3951481745), a = h(a, q), b = h(b, r), c = h(c, s), d = h(d, t);
    return (p(a) + p(b) + p(c) + p(d)).toLowerCase()
};

答案 6 :(得分:8)

只是为了好玩,

这是42行长,水平可容纳120个字符,并且看起来不错。快吗好吧-它足够快,并且与所有其他JS实现大致相同。

我只是想要一个在helpers.js文件中看起来不难看的东西,并且不会用20英里长的单线衬套降低SublimeText的速度。

这是我最喜欢的md5。

//  A formatted version of a popular md5 implementation.
//  Original copyright (c) Paul Johnston & Greg Holt.
//  The function itself is now 42 lines long.

function md5(inputString) {
    var hc="0123456789abcdef";
    function rh(n) {var j,s="";for(j=0;j<=3;j++) s+=hc.charAt((n>>(j*8+4))&0x0F)+hc.charAt((n>>(j*8))&0x0F);return s;}
    function ad(x,y) {var l=(x&0xFFFF)+(y&0xFFFF);var m=(x>>16)+(y>>16)+(l>>16);return (m<<16)|(l&0xFFFF);}
    function rl(n,c)            {return (n<<c)|(n>>>(32-c));}
    function cm(q,a,b,x,s,t)    {return ad(rl(ad(ad(a,q),ad(x,t)),s),b);}
    function ff(a,b,c,d,x,s,t)  {return cm((b&c)|((~b)&d),a,b,x,s,t);}
    function gg(a,b,c,d,x,s,t)  {return cm((b&d)|(c&(~d)),a,b,x,s,t);}
    function hh(a,b,c,d,x,s,t)  {return cm(b^c^d,a,b,x,s,t);}
    function ii(a,b,c,d,x,s,t)  {return cm(c^(b|(~d)),a,b,x,s,t);}
    function sb(x) {
        var i;var nblk=((x.length+8)>>6)+1;var blks=new Array(nblk*16);for(i=0;i<nblk*16;i++) blks[i]=0;
        for(i=0;i<x.length;i++) blks[i>>2]|=x.charCodeAt(i)<<((i%4)*8);
        blks[i>>2]|=0x80<<((i%4)*8);blks[nblk*16-2]=x.length*8;return blks;
    }
    var i,x=sb(inputString),a=1732584193,b=-271733879,c=-1732584194,d=271733878,olda,oldb,oldc,oldd;
    for(i=0;i<x.length;i+=16) {olda=a;oldb=b;oldc=c;oldd=d;
        a=ff(a,b,c,d,x[i+ 0], 7, -680876936);d=ff(d,a,b,c,x[i+ 1],12, -389564586);c=ff(c,d,a,b,x[i+ 2],17,  606105819);
        b=ff(b,c,d,a,x[i+ 3],22,-1044525330);a=ff(a,b,c,d,x[i+ 4], 7, -176418897);d=ff(d,a,b,c,x[i+ 5],12, 1200080426);
        c=ff(c,d,a,b,x[i+ 6],17,-1473231341);b=ff(b,c,d,a,x[i+ 7],22,  -45705983);a=ff(a,b,c,d,x[i+ 8], 7, 1770035416);
        d=ff(d,a,b,c,x[i+ 9],12,-1958414417);c=ff(c,d,a,b,x[i+10],17,     -42063);b=ff(b,c,d,a,x[i+11],22,-1990404162);
        a=ff(a,b,c,d,x[i+12], 7, 1804603682);d=ff(d,a,b,c,x[i+13],12,  -40341101);c=ff(c,d,a,b,x[i+14],17,-1502002290);
        b=ff(b,c,d,a,x[i+15],22, 1236535329);a=gg(a,b,c,d,x[i+ 1], 5, -165796510);d=gg(d,a,b,c,x[i+ 6], 9,-1069501632);
        c=gg(c,d,a,b,x[i+11],14,  643717713);b=gg(b,c,d,a,x[i+ 0],20, -373897302);a=gg(a,b,c,d,x[i+ 5], 5, -701558691);
        d=gg(d,a,b,c,x[i+10], 9,   38016083);c=gg(c,d,a,b,x[i+15],14, -660478335);b=gg(b,c,d,a,x[i+ 4],20, -405537848);
        a=gg(a,b,c,d,x[i+ 9], 5,  568446438);d=gg(d,a,b,c,x[i+14], 9,-1019803690);c=gg(c,d,a,b,x[i+ 3],14, -187363961);
        b=gg(b,c,d,a,x[i+ 8],20, 1163531501);a=gg(a,b,c,d,x[i+13], 5,-1444681467);d=gg(d,a,b,c,x[i+ 2], 9,  -51403784);
        c=gg(c,d,a,b,x[i+ 7],14, 1735328473);b=gg(b,c,d,a,x[i+12],20,-1926607734);a=hh(a,b,c,d,x[i+ 5], 4,    -378558);
        d=hh(d,a,b,c,x[i+ 8],11,-2022574463);c=hh(c,d,a,b,x[i+11],16, 1839030562);b=hh(b,c,d,a,x[i+14],23,  -35309556);
        a=hh(a,b,c,d,x[i+ 1], 4,-1530992060);d=hh(d,a,b,c,x[i+ 4],11, 1272893353);c=hh(c,d,a,b,x[i+ 7],16, -155497632);
        b=hh(b,c,d,a,x[i+10],23,-1094730640);a=hh(a,b,c,d,x[i+13], 4,  681279174);d=hh(d,a,b,c,x[i+ 0],11, -358537222);
        c=hh(c,d,a,b,x[i+ 3],16, -722521979);b=hh(b,c,d,a,x[i+ 6],23,   76029189);a=hh(a,b,c,d,x[i+ 9], 4, -640364487);
        d=hh(d,a,b,c,x[i+12],11, -421815835);c=hh(c,d,a,b,x[i+15],16,  530742520);b=hh(b,c,d,a,x[i+ 2],23, -995338651);
        a=ii(a,b,c,d,x[i+ 0], 6, -198630844);d=ii(d,a,b,c,x[i+ 7],10, 1126891415);c=ii(c,d,a,b,x[i+14],15,-1416354905);
        b=ii(b,c,d,a,x[i+ 5],21,  -57434055);a=ii(a,b,c,d,x[i+12], 6, 1700485571);d=ii(d,a,b,c,x[i+ 3],10,-1894986606);
        c=ii(c,d,a,b,x[i+10],15,   -1051523);b=ii(b,c,d,a,x[i+ 1],21,-2054922799);a=ii(a,b,c,d,x[i+ 8], 6, 1873313359);
        d=ii(d,a,b,c,x[i+15],10,  -30611744);c=ii(c,d,a,b,x[i+ 6],15,-1560198380);b=ii(b,c,d,a,x[i+13],21, 1309151649);
        a=ii(a,b,c,d,x[i+ 4], 6, -145523070);d=ii(d,a,b,c,x[i+11],10,-1120210379);c=ii(c,d,a,b,x[i+ 2],15,  718787259);
        b=ii(b,c,d,a,x[i+ 9],21, -343485551);a=ad(a,olda);b=ad(b,oldb);c=ad(c,oldc);d=ad(d,oldd);
    }
    return rh(a)+rh(b)+rh(c)+rh(d);
}

但实际上,我只是出于美学考虑而发布了它。另外,加上注释,它正好是4000字节。请不要问为什么。对于我的强迫症/反叛行为,我无法给出正确的解释。另外,谢谢保罗·约翰斯顿,谢谢格雷格·霍尔特。 (旁注:你们省略了一些 var 关键字,所以我可以随意添加它们。)

答案 7 :(得分:6)

目前最快的md5实施(基于Joseph Myers&#39;代码):

https://github.com/iReal/FastMD5

jsPerf comparaison:http://jsperf.com/md5-shootout/63

答案 8 :(得分:5)

我编写了测试来比较几个JavaScript哈希实现,包括这里提到的大多数MD5实现。 要运行测试,请转到http://brillout.github.io/test-javascript-hash-implementations/并等待一段时间。

似乎YaMD5R. Hill's answer实施速度最快。

答案 9 :(得分:5)

我只需要支持支持类型化数组的HTML5浏览器(DataView,ArrayBuffer等) 我想我采用了Joseph Myers代码并对其进行了修改以支持传递Uint8Array。我没有捕获所有的改进,并且仍然可能有一些char()数组工件可以改进。我需要这个来添加到PouchDB项目。

var PouchUtils = {};
PouchUtils.Crypto = {};
(function () {
    PouchUtils.Crypto.MD5 = function (uint8Array) {
        function md5cycle(x, k) {
            var a = x[0], b = x[1], c = x[2], d = x[3];

            a = ff(a, b, c, d, k[0], 7, -680876936);
            d = ff(d, a, b, c, k[1], 12, -389564586);
            c = ff(c, d, a, b, k[2], 17, 606105819);
            b = ff(b, c, d, a, k[3], 22, -1044525330);
            a = ff(a, b, c, d, k[4], 7, -176418897);
            d = ff(d, a, b, c, k[5], 12, 1200080426);
            c = ff(c, d, a, b, k[6], 17, -1473231341);
            b = ff(b, c, d, a, k[7], 22, -45705983);
            a = ff(a, b, c, d, k[8], 7, 1770035416);
            d = ff(d, a, b, c, k[9], 12, -1958414417);
            c = ff(c, d, a, b, k[10], 17, -42063);
            b = ff(b, c, d, a, k[11], 22, -1990404162);
            a = ff(a, b, c, d, k[12], 7, 1804603682);
            d = ff(d, a, b, c, k[13], 12, -40341101);
            c = ff(c, d, a, b, k[14], 17, -1502002290);
            b = ff(b, c, d, a, k[15], 22, 1236535329);

            a = gg(a, b, c, d, k[1], 5, -165796510);
            d = gg(d, a, b, c, k[6], 9, -1069501632);
            c = gg(c, d, a, b, k[11], 14, 643717713);
            b = gg(b, c, d, a, k[0], 20, -373897302);
            a = gg(a, b, c, d, k[5], 5, -701558691);
            d = gg(d, a, b, c, k[10], 9, 38016083);
            c = gg(c, d, a, b, k[15], 14, -660478335);
            b = gg(b, c, d, a, k[4], 20, -405537848);
            a = gg(a, b, c, d, k[9], 5, 568446438);
            d = gg(d, a, b, c, k[14], 9, -1019803690);
            c = gg(c, d, a, b, k[3], 14, -187363961);
            b = gg(b, c, d, a, k[8], 20, 1163531501);
            a = gg(a, b, c, d, k[13], 5, -1444681467);
            d = gg(d, a, b, c, k[2], 9, -51403784);
            c = gg(c, d, a, b, k[7], 14, 1735328473);
            b = gg(b, c, d, a, k[12], 20, -1926607734);

            a = hh(a, b, c, d, k[5], 4, -378558);
            d = hh(d, a, b, c, k[8], 11, -2022574463);
            c = hh(c, d, a, b, k[11], 16, 1839030562);
            b = hh(b, c, d, a, k[14], 23, -35309556);
            a = hh(a, b, c, d, k[1], 4, -1530992060);
            d = hh(d, a, b, c, k[4], 11, 1272893353);
            c = hh(c, d, a, b, k[7], 16, -155497632);
            b = hh(b, c, d, a, k[10], 23, -1094730640);
            a = hh(a, b, c, d, k[13], 4, 681279174);
            d = hh(d, a, b, c, k[0], 11, -358537222);
            c = hh(c, d, a, b, k[3], 16, -722521979);
            b = hh(b, c, d, a, k[6], 23, 76029189);
            a = hh(a, b, c, d, k[9], 4, -640364487);
            d = hh(d, a, b, c, k[12], 11, -421815835);
            c = hh(c, d, a, b, k[15], 16, 530742520);
            b = hh(b, c, d, a, k[2], 23, -995338651);

            a = ii(a, b, c, d, k[0], 6, -198630844);
            d = ii(d, a, b, c, k[7], 10, 1126891415);
            c = ii(c, d, a, b, k[14], 15, -1416354905);
            b = ii(b, c, d, a, k[5], 21, -57434055);
            a = ii(a, b, c, d, k[12], 6, 1700485571);
            d = ii(d, a, b, c, k[3], 10, -1894986606);
            c = ii(c, d, a, b, k[10], 15, -1051523);
            b = ii(b, c, d, a, k[1], 21, -2054922799);
            a = ii(a, b, c, d, k[8], 6, 1873313359);
            d = ii(d, a, b, c, k[15], 10, -30611744);
            c = ii(c, d, a, b, k[6], 15, -1560198380);
            b = ii(b, c, d, a, k[13], 21, 1309151649);
            a = ii(a, b, c, d, k[4], 6, -145523070);
            d = ii(d, a, b, c, k[11], 10, -1120210379);
            c = ii(c, d, a, b, k[2], 15, 718787259);
            b = ii(b, c, d, a, k[9], 21, -343485551);

            x[0] = add32(a, x[0]);
            x[1] = add32(b, x[1]);
            x[2] = add32(c, x[2]);
            x[3] = add32(d, x[3]);

        }

        function cmn(q, a, b, x, s, t) {
            a = add32(add32(a, q), add32(x, t));
            return add32((a << s) | (a >>> (32 - s)), b);
        }

        function ff(a, b, c, d, x, s, t) {
            return cmn((b & c) | ((~b) & d), a, b, x, s, t);
        }

        function gg(a, b, c, d, x, s, t) {
            return cmn((b & d) | (c & (~d)), a, b, x, s, t);
        }

        function hh(a, b, c, d, x, s, t) {
            return cmn(b ^ c ^ d, a, b, x, s, t);
        }

        function ii(a, b, c, d, x, s, t) {
            return cmn(c ^ (b | (~d)), a, b, x, s, t);
        }

        function md51(s) {
            txt = '';
            var n = s.length,
            state = [1732584193, -271733879, -1732584194, 271733878], i;
            for (i = 64; i <= s.length; i += 64) {
                md5cycle(state, md5blk(s.subarray(i - 64, i)));
            }
            s = s.subarray(i - 64);
            var tail = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0];
            for (i = 0; i < s.length; i++)
                tail[i >> 2] |= s[i] << ((i % 4) << 3);
            tail[i >> 2] |= 0x80 << ((i % 4) << 3);
            if (i > 55) {
                md5cycle(state, tail);
                for (i = 0; i < 16; i++) tail[i] = 0;
            }
            tail[14] = n * 8;
            md5cycle(state, tail);
            return state;
        }

        /* there needs to be support for Unicode here,
         * unless we pretend that we can redefine the MD-5
         * algorithm for multi-byte characters (perhaps
         * by adding every four 16-bit characters and
         * shortening the sum to 32 bits). Otherwise
         * I suggest performing MD-5 as if every character
         * was two bytes--e.g., 0040 0025 = @%--but then
         * how will an ordinary MD-5 sum be matched?
         * There is no way to standardize text to something
         * like UTF-8 before transformation; speed cost is
         * utterly prohibitive. The JavaScript standard
         * itself needs to look at this: it should start
         * providing access to strings as preformed UTF-8
         * 8-bit unsigned value arrays.
         */
        function md5blk(s) { /* I figured global was faster.   */
            var md5blks = [], i; /* Andy King said do it this way. */
            for (i = 0; i < 64; i += 4) {
                md5blks[i >> 2] = s[i]
                + (s[i + 1] << 8)
                + (s[i + 2] << 16)
                + (s[i + 3] << 24);
            }
            return md5blks;
        }

        var hex_chr = '0123456789abcdef'.split('');

        function rhex(n) {
            var s = '', j = 0;
            for (; j < 4; j++)
                s += hex_chr[(n >> (j * 8 + 4)) & 0x0F]
                + hex_chr[(n >> (j * 8)) & 0x0F];
            return s;
        }

        function hex(x) {
            for (var i = 0; i < x.length; i++)
                x[i] = rhex(x[i]);
            return x.join('');
        }

        function md5(s) {
            return hex(md51(s));
        }

        function add32(a, b) {
            return (a + b) & 0xFFFFFFFF;
        }

        return md5(uint8Array);
    };
})();

答案 10 :(得分:3)

我无法找到既快速又支持Unicode字符串的实现。

所以我创建了一个支持Unicode字符串并且仍然shows as faster(在撰写本文时)而不是当前最快的ascii-only-strings实现:

https://github.com/gorhill/yamd5.js

基于约瑟夫迈尔斯&#39;代码,但使用TypedArrays,以及其他改进。

答案 11 :(得分:1)

通过在图形卡上计算(在WebGL中实现散列算法),可以实现更快的散列,正如在那里讨论的关于SHA256:Is it possible to calculate sha256 hashes in the browser using the user's video card, eg. by using WebGL or Flash?

答案 12 :(得分:1)

js-md5支持UTF-8字符串,数组,ArrayBuffer,AMD ....

快点。 jsperf

答案 13 :(得分:1)

Node.js具有内置支持

const crypto = require('crypto')
crypto.createHash('md5').update('hello world').digest('hex')

上面的代码段计算字符串hello world的MD5十六进制字符串

此解决方案的优点是您不需要安装其他库。

我认为内置解决方案应该是最快的。如果没有,我们应该为Node.js项目创建Issue / PR。

答案 14 :(得分:0)

为什么不试试http://phpjs.org/functions/md5/

不幸的是,任何模拟脚本都限制了性能,但是这可以呈现真正的md5哈希。虽然我建议不要使用md5作为密码,因为它是一个快速渲染的哈希。

答案 15 :(得分:0)

也许这个包很有用
https://www.npmjs.com/package/pure-md5

console.time('latin');
const latin = md5('hello');
console.timeEnd('latin');

console.log('Привет: ', md5('Привет'));
console.log('嘿: ', md5('嘿'));
<script src="https://unpkg.com/pure-md5@latest/lib/index.js"></script>

答案 16 :(得分:-3)

您还可以查看我的md5 implementation。它应该是约。与上面发布的其他相同。不幸的是,性能受到内环的限制,这是不可能进行更多优化的。

答案 17 :(得分:-3)

如果您的应用程序的性能受到MD5的Javascript实现的限制,那么您确实做错了什么。考虑架构更改(提示:不经常使用MD5)