Question

我正在寻找一种比较2种不同List＆lt;＆gt;的优雅方式。集合并删除特定字段值匹配的项目。例如：客户对象

class Customer
{ 
    string CustomerName;
    string Email;
}

class Employee
{
    string EmployeeName;
    string EmployeeID;
 }

 List<Customer> Customers = new List<Customers(GetCustomers());
 List<Employee> Employees = new List<Employees(GetEmployees());

然后我知道我可以通过这样做从Employees列表中删除Customers列表中的Employe：

 Employees.RemoveAll(e => Customers.Any(c.CustomerName == e.EmployeeName));

我想知道的是我如何从客户列表中删除相应的员工？是否可以使用简单的语句或者我是否需要构建一些来处理这个问题？

Answer 1

怎么样：

Employees.Where(e => Customers.Any(c=> c.CustomerName == e.EmployeeName)).ToList()
    .ForEach(e=> { 
         Employees.Remove(e); 
         Customers.RemoveAll(c => c.CustomerName == e.EmployeeName);
     });

Answer 2

创建一个要删除的所有客户的列表，以及首先要删除的所有员工中的另一个。然后从原始列表中删除所有这些内容。我对lambda没有足够的认识从记忆中写出来，但它应该是可行的。

Answer 3

试试吧：

List<Customer> c = new List<Customer>();
c.Add(new Customer() {CustomerName = "test", Email = "email" });
c.Add(new Customer() { CustomerName = "test1", Email = "email1" });
c.Add(new Customer() { CustomerName = "test2", Email = "email2" });
c.Add(new Customer() { CustomerName = "test3", Email = "email3" });
List<Employee> e = new List<Employee>();
e.Add(new Employee() { EmployeeName = "test2", EmployeeID = "1" });
e.Add(new Employee() { EmployeeName = "test1", EmployeeID = "2" });
e.Add(new Employee() { EmployeeName = "test5", EmployeeID = "3" });
e.Add(new Employee() { EmployeeName = "test4", EmployeeID = "4" });

//remove from the Customers list the corresponding Employee 
e.RemoveAll(x => c.Any(y => y.CustomerName == x.EmployeeName));

foreach (var employee in e)
{
    //TODO: 
}

Answer 4

var inBoth = customers.Join(employees, customer => customer.CustomerName, employee => employee.EmployeeName, (customer, employee) => employee.EmployeeName).ToList();

customers.RemoveAll(customer => inBoth.Contains(customer.CustomerName));
employees.RemoveAll(employee => inBoth.Contains(employee.EmployeeName));

Answer 5

可以这样做：

var toBeDeleted = employees.Select(e => e.EmployeeName)
                           .Where(name => customers.Any(c => c.CustomerName == name))
                           .ToList();
customers.RemoveAll(c => toBeDeleted.Contains(c.CustomerName));
employees.RemoveAll(e => toBeDeleted.Contains(e.EmployeeName));

您可以使用Intersect来获取应删除的元素。我不知道任何一行命令可以做到这一点。

从列表<a> AND list<b> when a.Foo == b.Bar</b></a>中删除项目

5 个答案: