我正在尝试创建一个基于lon& amp;的路由LAT的。这是我到目前为止所做的,但它似乎没有正常工作。
<?xml version="1.0" encoding="UTF-8"?>
<kml xmlns="http://www.opengis.net/kml/2.2">
<Document>
<PlaceMark>
<name>test</name>
<description>test Desc</description>
<Point>
<coordinates>-80.54400115,43.4250264</coordinates>
<coordinates>-80.52674314,43.43127701</coordinates>
...
</Point>
</PlaceMark>
</Document>
<kml>
语法是否正确?当我在我的地图应用程序中加载它时,它不显示路线。
答案 0 :(得分:2)
<Point>
是一个单一的位置<LineString>
</kml>
需要<kml>
)。KML from example above on Google Maps
<?xml version="1.0" encoding="UTF-8"?><kml xmlns="http://www.opengis.net/kml/2.2"> <Document>
<Placemark><name>test</name>
<description>test Desc</description>
<LineString>
<coordinates>
-80.54400115,43.4250264
-80.52674314,43.43127701
-80.5274517,43.43458707
-80.53223781,43.43876923
-80.54385782,43.44993036
-80.53949137,43.45723788
-80.53950793,43.46780893
-80.53352615,43.4730443
-80.53491389,43.47816267
-80.54136061,43.48417145
-80.54163034,43.48439869
</coordinates>
</LineString>
</Placemark></Document>
</kml>