Question

我有一个简单的django设置，其中有一个名为' lists '的应用程序。我现在希望http://127.0.0.1:8000/lists显示此应用。所以我将主要的urls.py更改为以下内容：

from django.conf.urls import patterns, include, url

from django.contrib import admin
admin.autodiscover()

urlpatterns = patterns('',
    url(r'^lists/', include('lists.urls')),
    url(r'^admin/', include(admin.site.urls)),
)

我将位于lists-folder（我的app称为列表）的urls.py更改为以下内容：

from django.conf.urls import patterns, url
from lists import views

urlpatterns = patterns(
    url(r'^$', views.index, name='index')
)

据我所知，我完全按照the django tutorial中的说明操作，但当我访问http://127.0.0.1:8000/lists（没有尾随斜杠）时，它会给我以下错误：

Page not found (404) Request Method:    GET Request URL:    http://127.0.0.1:8000/lists

Using the URLconf defined in companyLists.urls, Django tried these URL patterns, in this order:

    ^lists/
    ^admin/

The current URL, lists, didn't match any of these.

当我访问http://127.0.0.1:8000/lists/（一个尾随斜杠）时，它会出现以下错误：

Page not found (404) Request Method:    GET Request URL:    http://127.0.0.1:8000/lists/

Using the URLconf defined in companyLists.urls, Django tried these URL patterns, in this order:

    ^admin/

The current URL, lists/, didn't match any of these.

我不明白为什么当我使用尾部斜杠访问url时它不再搜索^ lists /。有谁知道我在做错了什么？

欢迎所有提示！

Answer 1

您在列表patterns urls.py的开头缺少空字符串。

试试这个：

urlpatterns = patterns('',
    url(r'^$', views.index, name='index')
)

空白字符串是view prefix，您可以使用它来协助DRY主体。它用于为视图路径添加前缀。

例如，（扩展上面的示例）：

而不是：

urlpatterns = patterns('',
    url(r'^$', views.index, name='index'),
    url(r'^homepage$', views.homepage, name='index'),
    url(r'^lists$', views.lists, name='index'),
    url(r'^detail$', views.detail, name='index'),
)

您可以使用：

urlpatterns = patterns('views',
    url(r'^$', index, name='index'),
    url(r'^homepage$', homepage, name='index'),
    url(r'^lists$', lists, name='index'),
    url(r'^detail$', detail, name='index'),
)

让multiple view prefixes只对您的urlpatterns进行细分。

urlpatterns = patterns('views',
    url(r'^$', index, name='index'),
    url(r'^homepage$', homepage, name='index'),
    url(r'^lists$', lists, name='index'),
    url(r'^detail$', detail, name='index'),
)

urlpatterns += patterns('more_views',
    url(r'^extra_page$', extra_page, name='index'),
    url(r'^more_stuff$', something_else, name='index'),
)

无法让django网址发挥作用

1 个答案: