Question

我使用json使用json向ios app提供数据。但是在浏览器中运行代码时，它显示服务器错误。如果数据库中没有值，则会显示代码中提供的{"posts":null}。但是如果数据库中存在值，则会出现问题。它显示错误

Server error The website encountered an error while retrieving http://path to the server file/php/categoryitemlisting.php?category=11. It may be down for maintenance or configured incorrectly. Here are some suggestions: Reload this webpage later. HTTP Error 500 (Internal Server Error): An unexpected condition was encountered while the server was attempting to fulfill the request. 此错误仅发生在此php文件中。使用其他文件，我可以传输数据。

我的connection.php文件：

<?php
$link = mysql_connect("127.0.0.1","root","") or die('Cannot connect to the DB');
mysql_set_charset("utf8");
mysql_select_db('cotton',$link) or die('Cannot select the DB');
?>

Categoryitemlisting.php

 <?php

   require('connection.php');
   $item = array()       ;

   /* connect to the db */
      if(isset($_REQUEST['category']))
      {
            $k=$_REQUEST['category'];
        /* grab the posts from the db */
             // $k=11;
            $catid = mysql_query("SELECT entity_id FROM  field_data_field_cat WHERE field_cat_tid= $k");
            while($r = mysql_fetch_assoc($catid))
           {

               $category[] = $r['entity_id'];   
               foreach ( $category as $cat );
              {

                 $data= mysql_query("SELECT field_data_field_name.entity_id, field_data_field_name.field_name_value, file_managed.uri, field_data_field_sec.field_sec_tid FROM file_managed INNER JOIN ( field_data_field_thumb, field_data_field_name, field_data_field_sec ) ON ( file_managed.fid = field_data_field_thumb.field_thumb_fid AND field_data_field_name.entity_id = field_data_field_thumb.entity_id AND field_data_field_thumb.entity_id = field_data_field_sec.entity_id ) WHERE field_data_field_name.entity_id = $cat");  

               $items = mysql_fetch_assoc($data);
               $item[]= $items;
              }
            }
                $re="public:\/\/";
                $list = json_encode(array('posts'=>$item));
            $list = str_replace( $re, "http://localhost/sites/default/files/" ,$list);
                echo $list;

             @mysql_close($link);

      }

      else
      {
      echo "connection failed";
      }
?>

如何通过修复此错误来获取值？我不这么认为这是服务器的问题。如果代码中有任何其他错误？

Answer 1

查看你的php.ini并设置：

display_errors = on
error_reporting = E_ALL

如果display_error已关闭并且您的代码存在任何类型的问题（例如：解析错误），则您的响应将是500状态页面。

Answer 2

最后指出了这个问题......

服务器代码中的$k=$_REQUEST[' category'];中有一个空格。这导致了错误。

Drupal中的HTTP错误500（内部服务器错误）

2 个答案: