Question

我想在grails中创建一个选择框。我使用的是2.1.0。我有一个视图页面，显示一个名为class的选择框。但它没有显示出任何价值。当我将它渲染为json时，我在select的from属性中使用的列表工作正常。任何人都可以让我的组合框为我工作吗？以下是我的代码：

我的观看页面＆gt;＆gt;＆gt;

<g:form controller="admistratorAction" action="addStudent">
    <table class="centerTable">
        <div class="height"></div>
        <tr>
            <td><label>Full Name :</label></td>
            <td><g:textField name="fullname" id="fullname" class="field"/></td>
        </tr>
        <tr>
            <td> <label>Admission Class :</label></td>
            <td><g:select name="class" id="class"  class="field" from="${classList}" noSelection="['':'-Choose a class-']"/></td>
        </tr>
            <td colspan="2" align="right"><g:submitButton name="createSubmit" value="Create" class="button" onclick="return confirm('Are you sure???')"/></td>
        </tr>
    </table>
</g:form>

这是我的控制器＆gt;＆gt;

 package administrator

import common.classes.Classes
import grails.converters.JSON

class AdmistratorActionController {

def addStudent = {
    render "add student"
}


    def classList = {
        def classes = Classes.executeQuery("SELECT  c.classes FROM Classes c")
        def all_class = [classes : classes]
        render all_class as JSON
    }
}

Answer 1

您无需将其转换为JSON即可将其存储在gsp页面

中

class AdmistratorActionController {

    def addStudent = {
        def n = params.fullName
        def c = params.class
        // do something with them
    }

    def classList = {
        def classes = Classes.list()
        // pass details to view 'classList'
        [classList : classes]
    }
}

创建 - ＆gt;视图/ administratorAction / classList.gsp 你准备好了吗？你可以在其中获得$ {classList}

grails select不是渲染值

1 个答案: