Question

我可以

PROCEDURE dbo._ws_CallLogs_DeleteAll

OR

TABLE [dbo].[CachedPlan]

OR

VIEW [test].[MyView]

OR

FUNCTION [xyz].[ParseStringList]

作为输入

输出应为

案例1

string Type =  PROCEDURE
string DBOName = dbo
string obejctName = _ws_CallLogs_DeleteAll

案例2

string Type =  TABLE
string DBOName = dbo
string obejctName = CachedPlan

案例3

string Type = VIEW
string DBOName = test
string obejctName = MyView

案例4

string Type =  FUNCTION
string DBOName = xyz
string obejctName = ParseStringList

怎么做？

Answer 1

这是解析它的另一种方法：

static void Main(string[] args)
{
    var parser = new TSql100Parser(true);
    IList<ParseError> errors = new List<ParseError>();
    using (TextReader r = new StreamReader("sql.txt"))
    {
        var result = parser.GetTokenStream(r, errors);
        var results = result
            .Select((i, index) => (i.TokenType == TSqlTokenType.Create) ? index : -1)
            .Where(i => i >= 0)
            .Select(i => result.Skip(i + 1).TakeWhile(j =>
                (j.TokenType == TSqlTokenType.WhiteSpace
                || j.TokenType == TSqlTokenType.QuotedIdentifier
                || j.TokenType == TSqlTokenType.Identifier
                || j.TokenType == TSqlTokenType.Dot
                || j.TokenType == TSqlTokenType.Table
                || j.TokenType == TSqlTokenType.Procedure
                || j.TokenType == TSqlTokenType.View
                || j.TokenType == TSqlTokenType.Function
                ))
                .Where(j => (j.TokenType != TSqlTokenType.WhiteSpace 
                    && j.TokenType != TSqlTokenType.Dot))
                );

        foreach (var item in results)
        {
            var type = item.Where(i => (i.TokenType != TSqlTokenType.QuotedIdentifier
                || i.TokenType != TSqlTokenType.Identifier));
            Console.WriteLine("Type: {0}\tDbo: {1}\tObject: {2}",
                type.First().Text,
                type.Skip(1)
                    .Take(type.Count() - 2)
                    .Aggregate<TSqlParserToken, string>("", 
                        (a, b) => a + ((a == "") ? "" : ".") + b.Text),
                type.Last().Text);
        }
    }
}

您需要对以下命名空间的必需引用：

using Microsoft.Data.Schema.ScriptDom.Sql;
using Microsoft.Data.Schema.ScriptDom;

Answer 2

如果输入的格式相同，则可以使用此正则表达式。

(?<type>PROCEDURE|TABLE|VIEW|FUNCTION)\s+\[?(?<name>\w+)\]?[.]\[?(?<object>\w+)\]?

现在你可以得到像这样的匹配

Match m=Regex.Match(input,regex,RegexOptions.IgnoreCase);
m.Groups["type"].Value;//type
m.Groups["name"].Value;//name
m.Groups["object"].Value;//object

如何从提供的字符串中获取脚本类型，所有者名称和对象名称？

2 个答案: