Question

我有一张类似于：

的表格

id    user_id    value
----------------------------
1     2          colour
2     2          receive_email
3     3          colour
4     3          receive_email
5     3          receive_info

我按user_id对此表进行分组。我想要做的只是返回组不包含值'receive_info'。所以在上面的例子中，我会用user_id = 2返回一行。

我尝试过一些事情，这是最新的事情：

SELECT id, user_id, value  
FROM table 
GROUP BY user_id 
HAVING value NOT IN('receive_info');

我也尝试过：

SELECT id, user_id, value  
FROM table 
WHERE value NOT IN('receive_info') 
GROUP BY user_id;

当我这样做时，我会收到包含值='receive'的用户的记录。

任何人都知道我哪里出错了？

由于

Answer 1

SELECT  DISTINCT user_id
FROM    tableName a
WHERE   NOT EXISTS
        (
            SELECT  1
            FROM    tableName b
            WHERE   a.user_id = b.user_id AND
                    value = 'receive_info'
        )

SQLFiddle Demo

或使用LEFT JOIN

SELECT  DISTINCT a.user_id
FROM    tableName a
        LEFT JOIN tableName b
            ON  a.user_id = b.user_id AND
                b.value = 'receive_info'
WHERE   b.user_id IS NULL

SQLFiddle Demo

两个查询将输出

╔═════════╗
║ USER_ID ║
╠═════════╣
║       2 ║
╚═════════╝

在Mysql中查找不在GROUP BY中的值

1 个答案: