Question

我使用ksoap / ksoap2 api从j2me调用php webservice。

对于ksoap：

SoapObject client = new SoapObject(NAMESPACE, "ns2221:save_record");
        client.addProperty("cc", "1234560789");

        ByteArrayOutputStream bos = new ByteArrayOutputStream();
        XmlWriter xw = new XmlWriter(new OutputStreamWriter(bos));

        SoapEnvelope envelope = new SoapEnvelope(new ClassMap(Soap.VER11));
        envelope.setEncodingStyle("http://schemas.xmlsoap.org/soap/encoding/");
        envelope.setBody(client);
        envelope.write(xw);
        xw.flush();
        bos.write('\r');
        bos.write('\n');

        byte[] requestData = bos.toByteArray();
        String requestSOAPmesg = new String(requestData);
        System.out.println("request Soap Message: " + requestSOAPmesg);

        HttpTransport ht = new HttpTransport();
        ht.setUrl(url);
        ht.setSoapAction(NAMESPACE);
        SoapObject o = (SoapObject) ht.call(client);

已经使用..

和ksoap2

SoapObject client = new SoapObject("http://192.168.0.205:82/imageuploader/save_record.php#save_record", "ns8862:save_record");
        client.addProperty("cc", "1234560789");

        //Create Envelope for
        Object so=soapMsg;
        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.dotNet=false;
        envelope.bodyOut=client;
        System.out.println("Before Envelope");


        HttpTransport ht = new HttpTransport(url);
        ht.call("http://192.168.0.205:82/imageuploader/save_record.php#save_record", envelope);
        SoapObject o=(SoapObject) envelope.getResponse();

已经使用..

它让我回头

错误字符串：

faultstring：'操作'ns8862：save_record'未在此服务的WSDL中定义'faultactor：''detail：org.kxml2.kdom.Node@ea0ef881

在Web服务中，第一个标记ns8862：save_record每次传递4个数字的请求时都会更改。

任何解决方案？

Answer 1

检查网络服务是否有大写字母。该错误表明“save_record”未定义。也许是“Save_Record”或“saveRecord”。确保您遵守模板。

用于J2ME的kSoap API

1 个答案: