Question

我有一个使用jasypt加密ssn字段的Employee实体。以下是模拟定义：

@TypeDef(name = "encryptedString", typeClass = EncryptedStringType.class, parameters = {@Parameter(name = "encryptorRegisteredName",value = "strongHibernateStringEncryptor")})
@Entity
@Table(name="employee")
@NamedQueries(value = {
    @NamedQuery(name = "employee.getEmployeeBySSN", query = "SELECT employee from Employee employee WHERE employee.ssn=:ssn"),
    @NamedQuery(name = "employee.getEmployeeByName", query = "SELECT employee from Employee employee WHERE employee.name=:name")
    })
public class Employee {

    @Id @GeneratedValue
    private Long id;

    private String name;

    @Type(type = "encryptedString")
    private String ssn;
}

此实体包含两个用于获取员工的命名查询，一个具有名称，另一个具有ssn。 SSN字段使用jasypt加密。代码是模拟实现，因此我使用了以下基本配置：

public static void main(String[] args) throws SerialException, SQLException {

    //Configure jasypt encryptor
    PooledPBEStringEncryptor strongEncryptor = new PooledPBEStringEncryptor();
    strongEncryptor.setAlgorithm("PBEWITHMD5ANDDES");
    strongEncryptor.setPassword("jasypt");
    strongEncryptor.setPoolSize(2);

    //Register it with hibernate
    HibernatePBEEncryptorRegistry registry = HibernatePBEEncryptorRegistry.getInstance();
    registry.registerPBEStringEncryptor("strongHibernateStringEncryptor", strongEncryptor);

    //Get an entity manager factory
    EntityManagerFactory emf = Persistence.createEntityManagerFactory("helloworld");

    //Get an entity manager
    EntityManager em = emf.createEntityManager();
    EntityTransaction tx = em.getTransaction();
    tx.begin();

    //Create an employee
    Employee employee = new Employee();
    employee.setName("Vaibhav");
    employee.setSsn("1234567");
    em.persist(employee);

    tx.commit();

    EntityTransaction newtx = em.getTransaction();
    newtx.begin();

    //Search an employee with ssn
    Query queryObject1 = em.createNamedQuery("employee.getEmployeeBySSN");
    queryObject1.setParameter("ssn", "1234567");

    //No results here
    List employees1 = queryObject1.getResultList();

    newtx.commit();
    em.close();

}

employees1列表中没有结果。但是，当我运行以下命名查询时，我能够在employee对象中看到解密的ssn。

Query queryObject = em.createNamedQuery("employee.getEmployeeByName");
queryObject.setParameter("name", "Vaibhav");
List employees = queryObject.getResultList();
Employee employee1 = (Employee)employees.get(0);

我无法理解我的代码中是否存在错误，或者hibernate应该如何工作。在文档Integrating Jasypt with Hibernate 3.x or 4.x中，写有：

但加密设置了对Hibernate使用的限制：安全性标准确定了两种不同的加密操作相同的数据不应返回相同的值（由于使用随机数盐）。因此，没有设置的字段持久化时加密可以是你的WHERE子句的一部分搜索他们所属实体的查询。

因此，这意味着无法对加密字段执行搜索操作。

Answer 1

我使用的是随机盐生成器。添加零盐生成器后，我能够解决问题：

strongEncryptor.setSaltGenerator(new ZeroSaltGenerator());

无法在jasypt加密列上使用命名查询获取实体

1 个答案: