我想将图像上传到我网站文件夹中的文件夹,然后将其保存到数据库的路径并在控制图像中显示上传的图像。 当我执行我的页面时,图像上传成功,并保存到数据库,但它显示在图像控件上。
这是我的观点:
<%@ Page Language="VB" AutoEventWireup="false" CodeFile="Default.aspx.vb" Inherits="_Default" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title></title>
</head>
<body>
<form id="form1" runat="server">
<div>
</div>
<asp:FileUpload ID="FileUpload1" runat="server" />
<asp:Button ID="Button1" runat="server" Text="Button" />
<asp:Image ID="Image1" runat="server" Height="91px" Width="145px" />
</form>
<p>
</p>
</body>
</html>
这是我的代码:
Imports System.Data.SqlClient
Imports System.IO
Imports System.Data
Partial Class _Default
Inherits System.Web.UI.Page
Dim cn As SqlConnection
Protected Sub Button1_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles Button1.Click
If FileUpload1.PostedFile IsNot Nothing Then
Dim FileName As String = Path.GetFileName(FileUpload1.PostedFile.FileName)
'Save files to disk
FileUpload1.SaveAs(Server.MapPath("~/im/" & FileName))
'Add Entry to DataBase
Dim strQuery As String = "insert into dbo.images" & " values(@FileName, @FilePath)"
Dim cmd As New SqlCommand(strQuery)
cmd.Parameters.AddWithValue("@FileName", FileName)
cmd.Parameters.AddWithValue("@FilePath", "~/im/" & FileName)
cmd.CommandType = CommandType.Text
cmd.Connection = cn
Try
cn.Open()
cmd.ExecuteNonQuery()
Catch ex As Exception
Response.Write(ex.Message)
Finally
cn.Close()
cn.Dispose()
End Try
End If
End Sub
Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
cn = New SqlConnection("server=SEVO-PC;initial catalog=controle;integrated security=true")
End Sub
Protected Sub FileUpload1_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles FileUpload1.Load
Image1.ImageUrl = "im/" & FileUpload1.FileName
End Sub
End Class
答案 0 :(得分:0)
尝试以下编辑
Protected Sub FileUpload1_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles FileUpload1.Load
Image1.ImageUrl = Server.MapPath("/im/") & FileUpload1.FileName
End Sub