通过C#的GSMCOMM库发送SMS

时间:2013-05-13 12:47:00

标签: c# gsm

我已经开发了使用C#的GSMCOMM库发送短信的ac#应用程序。但是我面对的问题是,当我尝试使用gsmcomm objects.send消息方法发送消息时。有时它会给出异常该手机未连接,有时它会使异常端口无法打开。 我在下面分享我的代码: 用于将pc连接到手机gsm调制解调器的代码。有时它会发送消息而不给出任何例外 将手机连接到电脑的代码。

private bool ConnectPhone() 
    {
        string conectionStr = ConfigurationSettings.AppSettings["ConnectionString"].ToString();
        clsFileLogger.VerifyLogFileDirectory();
        clsFileLogger.WriteToLog("DB Connection: " + conectionStr);
        conn = new SqlConnection(@conectionStr);
        int port = Convert.ToInt32(ConfigurationSettings.AppSettings["port"]);
        int baudRate = Convert.ToInt32(ConfigurationSettings.AppSettings["baudRate"]);
        int timeout = Convert.ToInt32(ConfigurationSettings.AppSettings["timeout"]);
        gsmComm = new GsmCommMain(port, baudRate, timeout);
        try
        {
            Isconnected = false;
            if (gsmComm.IsConnected() == false)
            {
                gsmComm.Open();
            }

            Isconnected = gsmComm.IsConnected();

            clsFileLogger.WriteToLog("\nConnected with GSM Modam");
        }
        catch (Exception)
        {
            clsFileLogger.WriteToLog("\nUnable to open the port.");
        }
        return Isconnected;
    }


和发送短信的代码

  if (gsmComm.IsConnected() == false)
                    {
                        this.ConnectPhone();
                    }

                    pdu = new SmsSubmitPdu(strSMS, cellNO, "");
                    gsmComm.SendMessage(pdu);

 catch (Exception ex)
                {

                    throw ex;
                }

2 个答案:

答案 0 :(得分:4)

当你使用gsmcomm时...首先,在comboBox中列出你的comPorts 我是vb.net专家..你可以阅读这段代码并将其翻译成C# 1)在表单和form_load中创建一个组合框,编写此代码

 Private Sub Form1_Load(sender As Object, e As EventArgs) Handles MyBase.Load
        For Each prt In My.Computer.Ports.SerialPortNames
            comboBox1.Items.Add(prt)  
        Next
 End Sub

在您的全球范围内,编写此代码

            Public Property mymodem As GsmCommMain

在项目中添加一个子项,如下所示

   Private Sub connect()
    Try
        Cursor.Current = Cursors.WaitCursor
        If comboBox1.Text = "" Then Return
        If IsNothing(mymodem) Then mymodem = New GsmCommMain(comboBox1.Text)
        If Not mymodem.IsOpen Then mymodem.Open()
        Cursor.Current = Cursors.Default
    Catch ex As Exception
        richTextBox1.AppendText(ex.Message & vbCrLf) 'i add a richtextbox to my form for show exceptions and my produced declaration
    End Try
End Sub

之后放了一个手机号码的文本框..将其命名为txttel 还为textMessage设置了一个文本框..将其命名为txtMSG 按下按钮发送消息..将其命名为btnsend 剩下的代码将是这样的..

  Private Sub btnSend_Click(sender As Object, e As EventArgs) Handles btnSend.Click
            If String.IsNullOrEmpty(txtMSG.Text.Trim) Then Return
               SendSMS()

   End Sub


  Private Sub SendSMS()
     Try
          If Not mymodem.IsOpen Then connect()
          Dim pdu As New SmsSubmitPdu(txtMSG.Text.Trim & vbCr, txtTel.Text)
          mymodem.SendMessage(pdu)
          richTextBox1.AppendText("your message sent successfully")
      Catch ex As Exception
          richTextBox1.AppendText(ex.Message)
     End Try
  End Sub

最后一定要关闭你的端口..像这样

  Private Sub Form1_FormClosing(sender As Object, e As FormClosingEventArgs) Handles Me.FormClosing
    If Not IsNothing(mymodem) AndAlso mymodem.IsOpen Then
        mymodem.Close()
    End If
  End Sub

答案 1 :(得分:1)

试试这些指南(对我有帮助): http://www.codeproject.com/Articles/325731/Bulk-SMS-Sender http://www.codeproject.com/Articles/20420/How-To-Send-and-Receive-SMS-using-GSM-Modem

但似乎您的com-port打开问题不在您的代码中。尝试使用Teraterm应用程序测试您的端口。当你开始运行你的应用程序时,确保端口没有打开(它可能在上次启动后仍然打开)。