我在这里有一行find "$directory" -name "*.sh" -print0 | xargs -0 cp -t ~/bckup
备份以.sh结尾的所有内容。我如何为多个文件扩展名做到这一点?我尝试了不同的引号,括号和$的组合。他们都没有工作= \
我还想将某些文件扩展名备份到不同的文件夹中,我不知道如何搜索特定扩展名的文件名。
以下是我的整个代码:
#!/bin/bash
collect()
{
find "$directory" -name "*.(sh|c)" -print0 | xargs -0 cp -t ~/bckup #xargs handles files names with spaces. Also gives error of "cp: will not overwrite just-created" even if file didn't exist previously
}
echo "Starting log"
timelimit=10
echo "Please enter the directory that you would like to collect.
If no input in 10 secs, default of /home will be selected"
read -t $timelimit directory
if [ ! -z "$directory" ] #if directory doesn't have a length of 0
then
echo -e "\nYou want to copy $directory." #-e is so the \n will work and it won't show up as part of the string
else
directory=/home/
echo "Time's up. Backup will be in $directory"
fi
if [ ! -d ~/bckup ]
then
echo "Directory does not exist, creating now"
mkdir ~/bckup
fi
collect
echo "Finished collecting"
exit 0
答案 0 :(得分:1)
一个选项可能是使用内置逻辑或(来自查找手册页):
expr1 -o expr2
Or; expr2 is not evaluated if expr1 is true.
所以在你的情况下,你可以这样做:
find "$directory" -name '*.c' -o -name '*.sh'