我以网格格式显示了一些数据,现在我试图在最后一行点击删除按钮时删除该行,但是我收到错误。有人可以告诉我我犯了什么错误。我的代码:
<form action="deleteQuote.php" method="post">
<?php
require_once('config.php');
$conn = new mysqli(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE)
or die ('Cannot connect to db');
$result = $conn->query("SELECT quoteid,name,quote FROM `quotes`, category WHERE category.catid = quotes.catid and quotes.isactive = 1");
echo "<table>";
while ($row = $result->fetch_assoc()) {
echo "<tr><td><input type='hidden' name='delete_id' value=$row[quoteid] /></td> <td>$row[name]</td><td>$row[quote]</td>
<td><input type='submit' value='Delete' /></td></tr>";
}
echo "</table>";
?>
</form>
deleteQuote.php:
<?php
if(isset($_POST['delete_id']) && !empty($_POST['delete_id'])){
require_once('config.php');
$conn = new mysqli(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE)
or die ('Cannot connect to db');
$delete_id = mysql_real_escape_string($_POST['delete_id']);
echo "DELETE FROM quotes WHERE quoteid =".$delete_id;
$result = $conn->query("DELETE FROM quotes WHERE quoteid =".$delete_id);
}
header('Location: quotes.php');
&GT;
我收到以下错误:
警告:mysql_real_escape_string()[function.mysql-real-escape-string]:无法通过/ home / content中的套接字'/var/lib/mysql/mysql.sock'(2)连接到本地MySQL服务器第3行的/38/11053638/html/admin/deleteQuote.php
警告:mysql_real_escape_string()[function.mysql-real-escape-string]:无法在第6行的/home/content/38/11053638/html/admin/deleteQuote.php中建立到服务器的链接 删除引号WHERE quoteid = 警告:无法修改标头信息 - 已在/ home / content / 38/11053638 / html / admin / deleteQuote中发送的标头(在/home/content/38/11053638/html/admin/deleteQuote.php:6中开始输出)。第11行的php
答案 0 :(得分:1)
如果您尚未打开mysql连接,则无法使用mysql_real_escape_string()
。你使用mysqli而不是mysql,所以你需要使用等效的mysqli方法。
变化:
$delete_id = mysql_real_escape_string($_POST['delete_id']);
为:
$delete_id = $conn->real_escape_string($_POST['delete_id']);
但是,由于mysqli支持预处理语句,因此您应该使用它而不是连接字符串。然后你不必担心转义字符串。