我是Django的新手并尝试了一个简单的表格。我有一个模型类“Profile”,它定义了一个文件字段(schema_file),还有一个ModelForm类。当我尝试在浏览器中创建新的配置文件时,即使我在文件选择器中选择了一个文件,但是在schema_file字段中出现错误“此字段是必需的”,任何想法?我的课程如下:
class Profile(models.Model):
class Meta:
db_table = 'target_profiles'
class SchemaType:
XML = 1
CSV = 2
XLS = 3
JSON = 4
DB = 5
SCHEMA_CHOICES = (
(XML, 'XML'),
(CSV, 'CSV'),
(XLS, 'Excel'),
(JSON, 'JSON'),
(DB, 'Database'),
)
name = models.CharField(max_length=32, unique=True)
description = models.CharField(max_length=128, null=True, blank=True)
schema_type = models.IntegerField(choices=SchemaType.SCHEMA_CHOICES, default=SchemaType.CSV)
schema_file = models.FileField(upload_to='schema_files', max_length=64)
def __unicode__(self):
return self.name
class ProfileForm(forms.ModelForm):
class Meta:
model = Profile
视图:
def add_profile(request):
if request.method == 'POST':
form = ProfileForm(request.POST, request.FILES)
if form.is_valid():
cd = form.cleaned_data
return HttpResponseRedirect('/profiles')
else:
form = ProfileForm()
return render(request, 'profiles/add_profile.html', {'form': form})
答案 0 :(得分:38)
由于您尚未发布视图,我只能猜测它,因为您忘记包含request.FILES
:
form = ProfileForm(request.POST, request.FILES)
也许忘了在表单中添加enctype=multipart/form-data
。
答案 1 :(得分:1)
添加enctype =“ multipart / form-data”
<form enctype="multipart/form-data" method="post">
{% csrf_token %}
{{ form.as_p }}
<button type="submit">Upload</button>
</form>