这是输入XML:
<Move-Afile>
<Afile>
<Item>
<PackNumber>1234</PackNumber>
</Item>
<Item>
<PackNumber>567</PackNumber>
</Item>
<Item>
<PackNumber>567</PackNumber>
</Item>
<Item>
<PackNumber>126</PackNumber>
</Item>
<Item>
<PackNumber>876</PackNumber>
</Item>
</Afile>
</Move-Afile>
<Item>
是一个无界元素,其中包含<PackNumber>
作为子元素。对于每个包数,我们需要递增计数器变量,但是这里存在一个条件,就像前一个<PackNumber>
等于当前<PackNumber>
一样,我们必须忽略计数器(不需要递增),就像低于输出。
在for-each
内,我们可以像XSLT样本一样获得计数器吗?
这是我的XSLT模板
<xsl:template match="/">
<A>
<target>
<xsl:for-each select="/inp1:Move-Afile/inp1:Afile/inp1:Item/inp1:PalletNumber">
<xsl:variable name="count">
<!-- get the count here-->
</xsl:variable>
<counter>$count</counter>
<PNumber><xsl:value-of select="."/></PNumber>
</xsl:for-each>
</target>
</A>
</xsl:template>
这是XML输出:
<A>
<target>
<Item>
<counter>1</counter><!-- if previous <PackNumber> is not equal to current <PackNumber> increment the count-->
<PNumber>1234</PNumber>
</Item>
<Item>
<counter>2</counter><!-- if previous <PackNumber> is not equal to current <PackNumber> increment the count-->
<PNumber>567</PNumber>
</Item>
<Item><!-- if previous <PackNumber> is equal to current <PackNumber> ignore the count-->no need to increment
<PNumber>567</PNumber>
</Item>
<Item>
<counter>3</counter><!-- if previous <PackNumber> is not equal to current <PackNumber> increment the count-->
<PNumber>126</PNumber>
</Item>
<Item><!-- if previous <PackNumber> is equal to current <PackNumber> ignore the count-->no need to increment
<PNumber>126</PNumber>
</Item>
</target>
</A>
XML输出2:
<?xml version="1.0"?>
<A>
<target>
<counter>1</counter>
<PNumber>1234</PNumber>
<counter>2</counter>
<PNumber>567</PNumber>
<!-- IF PNumber is equal we have to ignore the Total loop -->
<counter>3</counter>
<PNumber>126</PNumber>
<counter>4</counter>
<PNumber>876</PNumber>
</target>
</A>
答案 0 :(得分:4)
Try this:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="text()" />
<xsl:template match="PackNumber">
<xsl:if test="not(preceding::PackNumber =.)" >
<!-- if previous <PackNumber> is not equal to current <PackNumber> t-->
<counter>
<xsl:value-of select="count(preceding::PackNumber[not(preceding::PackNumber= .)])+1"/>
</counter>
</xsl:if>
<PNumber>
<xsl:value-of select="."/>
</PNumber>
</xsl:template>
<xsl:template match="/">
<A>
<target>
<xsl:apply-templates select="//Item"/>
</target>
</A>
</xsl:template>
</xsl:stylesheet>
根据更改的问题 更新:
在此处获取计数(在每个循环内部作为变量)
试试这个:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="text()" />
<xsl:template match="PackNumber" mode="count">
<xsl:value-of select="count(preceding::PackNumber
[not(preceding::PackNumber= .)and not( . = current()/. ) ])+1"/>
</xsl:template>
<xsl:template match="/">
<A>
<target>
<xsl:for-each select="//Item/PackNumber">
<xsl:variable name="count">
<xsl:apply-templates select="." mode="count"/>
</xsl:variable>
<counter>
<xsl:value-of select="$count"/>
</counter>
<PNumber>
<xsl:value-of select="."/>
</PNumber>
</xsl:for-each>
</target>
</A>
</xsl:template>
</xsl:stylesheet>
更新输出:
<?xml version="1.0"?>
<A>
<target>
<counter>1</counter>
<PNumber>1234</PNumber>
<counter>2</counter>
<PNumber>567</PNumber>
<counter>2</counter>
<PNumber>567</PNumber>
<counter>3</counter>
<PNumber>126</PNumber>
<counter>4</counter>
<PNumber>876</PNumber>
</target>
</A>
答案 1 :(得分:3)
这是一个简短且非常有效的解决方案,使用Muenchian grouping:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="kPackNByVal" match="PackNumber" use="."/>
<xsl:template match="Afile">
<A>
<target>
<xsl:apply-templates select=
"*/*[generate-id() = generate-id(key('kPackNByVal',.)[1])]"/>
</target>
</A>
</xsl:template>
<xsl:template match="PackNumber">
<counter><xsl:value-of select="position()"/></counter>
<PNumber><xsl:value-of select="."/></PNumber>
</xsl:template>
</xsl:stylesheet>
在提供的XML文档上应用此转换时:
<Move-Afile>
<Afile>
<Item>
<PackNumber>1234</PackNumber>
</Item>
<Item>
<PackNumber>567</PackNumber>
</Item>
<Item>
<PackNumber>567</PackNumber>
</Item>
<Item>
<PackNumber>126</PackNumber>
</Item>
<Item>
<PackNumber>876</PackNumber>
</Item>
</Afile>
</Move-Afile>
产生了想要的正确结果:
<A>
<target>
<counter>1</counter>
<PNumber>1234</PNumber>
<counter>2</counter>
<PNumber>567</PNumber>
<counter>3</counter>
<PNumber>126</PNumber>
<counter>4</counter>
<PNumber>876</PNumber>
</target>
</A>
答案 2 :(得分:1)
如果您需要的结果是您在第二个 XML示例中显示的结果,那么这个样式表就是您所需要的。
所有这一切只是复制PackNumber
仅来自之前没有匹配Item
的{{1}}元素。
计算的次数比前一个没有匹配的前一个PackNumber
元素的数量多一个。
Item
<强>输出强>
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:strip-space elements="*"/>
<xsl:output method="xml" indent="yes" encoding="UTF-8" omit-xml-declaration="yes"/>
<xsl:template match="/">
<A>
<target>
<xsl:apply-templates select="*"/>
</target>
</A>
</xsl:template>
<xsl:template match="Item">
<xsl:if test="not(PackNumber = preceding-sibling::Item/PackNumber)">
<counter>
<xsl:value-of select="1+count(preceding-sibling::Item[not(PackNumber = preceding-sibling::Item/PackNumber)])"/>
</counter>
<xsl:copy-of select="PackNumber"/>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
答案 3 :(得分:-1)
不是每次都使用计数器变量并尝试递增其值(由于xsl中的变量实际上是常量而不会发生这种情况),请尝试使用position()
,它可以作为唯一的递增标识符。以下是使用position()
:
<xsl:variable name="counterAlias" select="position()"/>