Question

我有这个查询来获取两个用户之间的最后一条消息。

    SELECT  f.*
    FROM
            (
                SELECT  *
                FROM    messages a
                WHERE  (LEAST(a.sender, a.receiver), GREATEST(a.sender, a.receiver), a.timestamp) 
                        IN  (   
                                SELECT  LEAST(b.sender, b.receiver) AS x, 
                                        GREATEST(b.sender, b.receiver) AS y,
                                        MAX(b.timestamp) AS msg_time
                                FROM    messages b
                                GROUP   BY x, y
                            ) 
            ) f
    WHERE   :user_id IN (f.sender, f.receiver)
    ORDER   BY f.timestamp DESC

我在这里得到它，对我来说有点复杂。

我需要修改它才能在:user_id未删除会话时获取最后一条消息。

该表有4个重要字段：sender, receiver, sender_deleted, receiver_deleted。

当用户想要删除对话时，我会运行查询以将已删除的字段设置为1。

用户4删除了会话的表格示例：

sender   receiver    sender_deleted     receiver_deleted         message

  4         17             1                   0           user 4 to 17 message
  17        4              0                   1           user 17 to 4 message

我需要修改上述查询，以便:user_id = 4返回为空，但如果:user_id = 17返回上次发送的消息。

我希望我能很好地解释我想做什么。

Answer 1

这应该做你想要的：

SELECT  f.*
FROM
        (
            SELECT  *
            FROM    messages a
            WHERE  (LEAST(a.sender, a.receiver), GREATEST(a.sender, a.receiver), a.timestamp) 
                    IN  (   
                            SELECT  LEAST(b.sender, b.receiver) AS x, 
                                    GREATEST(b.sender, b.receiver) AS y,
                                    MAX(b.timestamp) AS msg_time
                            FROM    messages b
                            GROUP   BY x, y
                        ) 
        ) f
WHERE   (:user_id = f.sender AND f.sender_deleted != 1)
    OR (:user_id = f.receiver AND f.receiver_deleted != 1)
ORDER   BY f.timestamp DESC

MySQL Complex Query，用户对话

1 个答案: