MySQL查询从表中获取主键（customer_id）并将其与当前会话ID（customer_id）进行比较

Question

我运行此代码时出现此错误。

解析错误：第32行的C：\ xampp \ htdocs \ pta \ cc11205 \ booking.php中的语法错误，意外的“”“（T_CONSTANT_ENCAPSED_STRING）

 $querycust = mysql_query(" SELECT * FROM customer WHERE customer_id = ".$_SESSION['customer_id']" ");

TQ

Answer 1

您的查询中存在语法错误，请将查询更改为此

$querycust = mysql_query(" SELECT * FROM customer WHERE customer_id = '".$_SESSION['customer_id']."' ");

Answer 2

你在字符串中缺少连接符号。为清楚起见，我宁愿将seeion存储在一个变量中，例如

$session_var = $_SESSION['customer_id'];
$querycust = mysql_query(" SELECT * FROM customer WHERE customer_id = $session_var");

还考虑使用PDO或MySQLI扩展名来阻止SQL Injection。

Answer 3

逃避你的报价。

" SELECT * FROM customer WHERE customer_id = \".$_SESSION['customer_id']\" "