Question

正如我在标题中提到的，我在ListFragment中有2个ListView（让我们称之为A和B），只有一个onListItemClick。

当我点击列表A的一行时，我的onListItemClick被称为罚款。但当我点击列表B的一行时，没有任何反应。

这就是我所拥有的：

<!-- LIST A -->
<ListView
    android:id="@id/android:list"
    android:layout_width="match_parent"
    android:layout_height="wrap_content" >
</ListView>

<!-- Separator -->
<View
    android:layout_width="fill_parent"
    android:layout_height="1dp"
    android:background="@android:color/darker_gray"/>

<!-- LIST B -->
<ListView
    android:id="@+id/listCompany"
    android:layout_width="match_parent"
    android:layout_height="wrap_content" >
</ListView>

这是我的ListFragment：

public class ClientsActivity extends ListFragment {
    OnClientSelectedListener mClientListener;


public interface OnClientSelectedListener {
        public void onEmployeeSelected(int id);
        public void onCompanySelected(int id);
    }

@Override
    public void onAttach(Activity activity) {
        super.onAttach(activity);
        try {
        mClientListener = (OnClientSelectedListener) activity;
        } catch (ClassCastException e) {
            throw new ClassCastException(activity.toString() + " you must implement OnClientSelectedListener ");
    }
}

@Override
    public void onListItemClick(ListView l, View v, int position, long id) {
    super.onListItemClick(l, v, position, id);

    Log.e("onListItemClick","called with " + position + " : "+l.getId() + " and " + android.R.id.list);
        int id = position; 
    if (l.getId() == android.R.id.list) {
           mClienteListener.onEmployeeSelected(id);
       } else if (l.getId() == R.id.listCompany) {
           mClienteListener.onCompanySelected(id);
       }
}

然后在我的主要FragmentActivity中，我实现了OnClientSelectedListener接口。我认为这必须与我的ListViews中的android：id。我不知道如何在单击List B的行时调用onListItemClick。任何帮助都会被贬低。

解决方案：

在我的ListFragment的onCreateView中，我有：

 public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {

    View view = inflater.inflate(R.layout.activity_clientes, container, false);

            //LIST A
    listEmploees(view);

            //LIST B
    listCompanies(view);
...
}

private void listCompanies(View view){
    CompanyqliteDao companyDao = new CompanyqliteDao ();
            //I get all the companies from DB
    mCursorCompany = companyDao.listCompany(getActivity());

    if(mCursorCompany.getCount()>0){
        String[] from = new String[] { "name", "phone"};
        int[] to = new int[] { R.id.textViewNameIzq,  R.id.textViewNameCent };
        ListView lvCompanies = (ListView) view.findViewById (R.id.listCompany);

                    //I have a custom adapter
        ListClientCursorAdapter notes = new ListClientsCursorAdapter(contexto, R.layout.activity_fila_cliente, mCursorCompany, from, to, 0);
        lvCompanies .setAdapter(notes);


        lvCompanies.setOnItemClickListener(new OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> adapter, View view, int position, long arg)   {
                onListItemClick(lvCompanies,view,position,arg);
            }
        });

    }
}


private void listEmploees(View view){
    EmployeeSqliteDao employeeDao = new EmployeeSqliteDao();
            //Get the list from DB
    mCursorEmployee = employeeDao.listEmployees(getActivity());

    if(mCursorEmployee.getCount()>0){
        String[] from = new String[] { "name", "phone"};
        int[] to = new int[] { R.id.textViewNameIzq,  R.id.textViewNameCent};
        ListView lvEmployees = (ListView) view.findViewById (android.R.id.list);

        ListClientsCursorAdapter notes = new ListClientesCursorAdapter(context, R.layout.activity_fila_cliente, mCursorEmployee, from, to, 0);
        lvEmployees.setAdapter(notes);
                    //NOTE THAT I DONT HAVE TO SET A LISTENER FOR THIS ONE, AUTOMATICALLY
                    // THE onListItemClick IS CALLED

    }

Answer 1

您需要获取第二个ListView的引用，并且需要将onItemClickListener附加到它。

因为ListFragment会为标识为@id/android:list的listView附加onItemClckListener

尝试在onCreateView

中获取参考

修改

ListView list2=view.findViewById(R.id.listCompany); list2.setOnItemClickListener(new AdapterView.OnItemClickListener() { @Override public void onItemClick(AdapterView<?> adapter, View view, int position, long arg) { onListItemClick(adapter,view,position,arg); } });

Answer 2

您需要将ListFragment更改为Fragment，然后分别引用两个ListView并分配他们的听众：

ListView list = (ListView)findViewById(R.id.list);
ListView listCompany = (ListView)findViewById(R.id.listCompany);

list.setAdapter(...)
list2.listCompany(...)

每个ListView ListFragment一个ListViews，一个Fragment多个ListViews，但ListFragment

中只有两个{{1}}

2 ListFragment中的ListView只有一个onListItemClick

2 个答案: