我不是MySQL专业人员我只是想创建一个访问MySQL数据库的简单java应用程序(例如着名的书籍/作者数据库)并对其进行操作(即添加,更新,删除)。
问题是,当我尝试使用
删除时,有两个表具有多对多的关系(例如,作者表和书籍表)DELETE FROM tableName WHERE someColumnName = 'someValue'
它抛出MySQLIntegrityConstraintViolationException,并显示消息“无法删除或更新父行:外键约束失败”
我知道这是因为“多对多”的关系,但实际上我不知道该怎么做,因为我不是MySQL的专业人士。任何帮助将不胜感激。谢谢。
修改 这是数据库
DROP DATABASE IF EXISTS books;
CREATE DATABASE books;
USE books;
CREATE TABLE Authors
(
AuthorID int NOT NULL AUTO_INCREMENT PRIMARY KEY,
FirstName varchar(30) NOT NULL,
LastName varchar(30) NOT NULL
) ;
CREATE TABLE Titles
(
ISBN varchar(20) NOT NULL PRIMARY KEY,
Title varchar(100) NOT NULL,
EditionNumber int NOT NULL,
Copyright varchar(4) NOT NULL
) ;
CREATE TABLE AuthorISBN
(
AuthorID int NOT NULL,
ISBN varchar(20) NOT NULL,
FOREIGN KEY (AuthorID) REFERENCES Authors(AuthorID) ON DELETE SET NULL,
FOREIGN KEY (ISBN) References Titles(ISBN) ON DELETE SET NULL
) ;
INSERT INTO Authors (FirstName,LastName) VALUES ('Paul','Deitel') ;
INSERT INTO Authors (FirstName,LastName) VALUES ('Harvey','Deitel') ;
INSERT INTO Authors (FirstName,LastName) VALUES ('Abbey','Deitel') ;
INSERT INTO Authors (FirstName,LastName) VALUES ('Michael','Morgano') ;
INSERT INTO Authors (FirstName,LastName) VALUES ('Eric','Kern') ;
INSERT INTO Titles (ISBN,Title,EditionNumber,Copyright) VALUES ('0132152134','Visual Basic 2010 How to Program',5,'2011') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (1,'0132152134') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (2,'0132152134') ;
INSERT INTO Titles (ISBN,Title,EditionNumber,Copyright) VALUES ('0132151421','Visual C# 2010 How to Program',4,'2011') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (1,'0132151421') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (2,'0132151421') ;
INSERT INTO Titles (ISBN,Title,EditionNumber,Copyright) VALUES ('0132575663','Java How to Program',9,'2012') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (1,'0132575663') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (2,'0132575663') ;
INSERT INTO Titles (ISBN,Title,EditionNumber,Copyright) VALUES ('0132662361','C++ How to Program',8,'2012') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (1,'0132662361') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (2,'0132662361') ;
INSERT INTO Titles (ISBN,Title,EditionNumber,Copyright) VALUES ('0132404168','C How to Program',6,'2010') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (1,'0132404168') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (2,'0132404168') ;
INSERT INTO Titles (ISBN,Title,EditionNumber,Copyright) VALUES ('013705842X','iPhone for Programmers: An App-Driven Approach',1,'2010') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (1,'013705842X') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (2,'013705842X') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (3,'013705842X') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (4,'013705842X') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (5,'013705842X') ;
INSERT INTO Titles (ISBN,Title,EditionNumber,Copyright) VALUES ('0132121360','Android for Programmers: An App-Driven Approach',1,'2012') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (1,'0132121360') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (2,'0132121360') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (3,'0132121360') ;
INSERT INTO AuthorISBN (AuthorID,ISBN) VALUES (4,'0132121360') ;
答案 0 :(得分:1)
可能是因为您将CONSTRAINT
onUpdate
和onDelete
设置为RESTRICT
。您可以将其更改为SET NULL
,然后可以删除。
请参阅有关MySQL文档的this section。
修改强>
超越SET NULL
,您也可以尝试NO ACTION
选项。
IE:
FOREIGN KEY(ord_no,book_id) REFERENCES neworder(ord_no,book_id)
ON UPDATE SET NULL ON DELETE SET NULL
OR
FOREIGN KEY(ord_no,book_id) REFERENCES neworder(ord_no,book_id)
ON UPDATE NO ACTION ON DELETE NO ACTION
希望它有所帮助。
答案 1 :(得分:0)
通过移除NOT NULL
字词并在 FOREIGN KEY 语句后添加ON DELETE CASCADE
和ON UPDATE CASCADE
来解决问题。