Question

我在这里上了两节课“学生”和“课程”：

@XmlRootElement
class Student {
    private String name;
    private HashMap<String, Course> courses;

    public Student() {}
    public Student(String name, HashMap<String, Course> courses) {
        super();
        this.name = name;
        this.courses = courses;
    }
    // -------------------------getters
    @XmlAttribute(name="name")
    public String getName() {
        return name;
    }

    @XmlElement(name = "course")
    public HashMap<String, Course> getCourses() {
        return courses;
    }

    //---------------------------setters

    public void setName(String name) {
        this.name = name;
    }
    public void setCourses(HashMap<String, Course> courses) {
        this.courses = courses;
    }

}



@XmlRootElement
class Course {
    private String id;
    private String name;

    public Course() {}
    public Course(String id, String name) {
        super();
        this.id = id;
        this.name = name;
    }

    @XmlID
    @XmlAttribute(name = "id")
    public String getId() {
        return id;
    }
    @XmlAttribute(name = "name")
    public String getName() {
        return name;
    }
    public void setId(String id) {
        this.id = id;
    }
    public void setName(String name) {
        this.name = name;
    }

}

我想使用JaxB注释将Student类序列化为类似以下内容：

<Student name="David">
    <courses>
        <Course id="1" name="Fundamentals of Programming"/>
        <Course id="2" name="Advanced Programming">
    </courses>
</Student>

请注意，我希望Student的courses字段为HashMap，当解组序列化Object时，使用id作为每个Course的键。

Answer 1

您可以在此用例中使用XmlAdapter。 XmlAdapter允许您以编程方式将对象转换为另一种类型，以便进行编组/解组。对于您的用例，您将HashMap转换为集合为Course的对象的实例。

http://blog.bdoughan.com/2010/07/xmladapter-jaxbs-secret-weapon.html

像集合属性一样序列化HashMap

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