Question

我使用scapy在python中创建了一个数据包嗅探器，但是它仍然存在于多线程中。

def sniffer(ip):
    filter_str = "icmp and host " + ip
    packets=sniff(filter=filter_str,count=20)
    status= False
    for p in packets:
        packet_load=str(p['Raw'].load)
        if packet_load.find("@@")!= -1:
                status=True
                log_thread = Thread(target=logger,args=(packets,))
                log_thread.start()
                log_thread.join()
                break
    if status==True:
        print "Suspicious Packets sniffed!!"

    user_ip = raw_input("Do you want to continue sniffing???(y/n)")
    while 1:
        if user_ip=="y" or user_ip=="Y":
            new_thread = Thread(target=sniffer, args=(ip,))
            new_thread.start()
            new_thread.join()
        else:
            #need somthing to quit the program
   return

在这里，我的嗅探器一次嗅探20个数据包并等待用户输入以进一步嗅探。但是，如果用户输入“n”作为输入，则程序将挂起。理想情况下，如果用户输入'n'，我希望程序退出。我能在这里知道我做错了吗？

Answer 1

在编写有限循环时，

while 1很少是一个不错的选择。请尝试使用标志：

leaving = False
while not leaving:

    user_ip = raw_input("Do you want to continue sniffing???(y/n)")
    if user_ip.lower() == 'y':
        new_thread = Thread(target=sniffer, args=(ip,))
        new_thread.start()
        new_thread.join()
    elif user_ip.lower() == 'n':
        print "Leaving sniffer"
        leaving = True
return

python multithreaded sniffer-从线程退出

1 个答案: