我为raquetball模拟做了一个家庭作业。我正在试图弄清楚如何扩展程序以解决关闭并返回每个玩家的数量。我在simNGames()中添加了一个循环来计算关闭。我想返回这些值并在摘要中打印出来。
def simNGames(n, probA, probB):
winsA = 0
winsB = 0
shutoutA = 0
shutoutB = 0
for i in range(n):
scoreA, scoreB = simOneGame(probA, probB)
if scoreA > scoreB:
winsA = winsA + 1
else:
winsB = winsB + 1
for i in range(n):
scoreA, scoreB = simOneGame(probA, probB)
if scoreA == 15 and scoreB == 0:
shutoutA = shutoutA + 1
if scoreA == 0 and scoreB == 15:
shutoutB = shutoutB + 1
return winsA, winsB, shutoutA, shutoutB ## The program breaks when I add
## shutoutA, and shutoutB as return val
如果有人能引导我朝着正确的方向前进,我将不胜感激。我得到一个ValueError:当我将返回值添加到返回值时,解包(预期为2)的值太多了。这是整个计划:
from random import random
def main():
probA, probB, n = GetInputs()
winsA, winsB = simNGames(n, probA, probB)
PrintSummary(winsA, winsB)
def GetInputs():
a = eval(input("What is the probability player A wins the serve? "))
b = eval(input("What is the probablity player B wins the serve? "))
n = eval(input("How many games are they playing? "))
return a, b, n
def simNGames(n, probA, probB):
winsA = 0
winsB = 0
shutoutA = 0
shutoutB = 0
for i in range(n):
scoreA, scoreB = simOneGame(probA, probB)
if scoreA > scoreB:
winsA = winsA + 1
else:
winsB = winsB + 1
for i in range(n):
scoreA, scoreB = simOneGame(probA, probB)
if scoreA == 15 and scoreB == 0:
shutoutA = shutoutA + 1
if scoreA == 0 and scoreB == 15:
shutoutB = shutoutB + 1
return winsA, winsB
def simOneGame(probA, probB):
serving = "A"
scoreA = 0
scoreB = 0
while not gameOver(scoreA, scoreB):
if serving == "A":
if random() < probA:
scoreA = scoreA + 1
else:
serving = "B"
else:
if random() < probB:
scoreB = scoreB + 1
else:
serving = "A"
return scoreA, scoreB
def gameOver(a, b):
return a == 15 or b == 15
def PrintSummary(winsA, winsB):
n = winsA + winsB
print("\nGames simulated:", n)
print("Wins for A: {0} ({1:0.1%})".format(winsA, winsA/n))
print("Wins for B: {0} ({1:0.1%})".format(winsB, winsB/n))
if __name__ == '__main__': main()
答案 0 :(得分:2)
调用该函数时:
winsA, winsB = simNGames(n, probA, probB)
您只期望两个值(winsA,winsB),但返回四个。