我正在尝试用可以与JLabel一起使用的东西替换setCharAt ...我一直在oracle doc寻找解决方案。我不知道我是在寻找错误的东西,还是只是不存在......如果它不存在我怎么能解决这个问题呢?我理解我的命名惯例是关闭的,并将尽快更改它们......
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import javax.swing.*;
public class HangmanPanel extends JPanel {
static Boolean FOUND;
private static final long serialVersionUID = -5793357804828609325L;
public static String answerKey() {
//get random array element
String array[] = new String[10];
array[0] = "hamlet";
array[1] = "mysts of avalon";
array[2] = "the iliad";
array[3] = "tales from edger allan poe";
array[4] = "the children of hurin";
array[5] = "the red b" +
"+adge of courage";
array[6] = "of mice and men";
array[7] = "utopia";
array[8] = "chariots of the gods";
array[9] = "a brief history of time";
ArrayList<String> list = new ArrayList<String>(Arrays.asList(array));
Collections.shuffle(list);
String s = list.get(0);
return s;
}
public StringBuilder dashReplace(String s) {
//replace non-white space char with dashes and creates StringBuilder Object
String tW = s.replaceAll("\\S", "-");
System.out.print(tW + "\n");
StringBuilder AnswerKey = new StringBuilder(tW);
return AnswerKey;
}
public static int findAndReplace(String s, JLabel answerKey, String sc,
char ch) {
//find position of user input and replace
int pos = -1;
FOUND = false;
while(true){
pos = s.indexOf(sc, pos+1);
if(pos < 0){
break;
}else{
FOUND = true;
//setCharAt dosen't work for JLable
answerKey.setCharAt(pos, ch);
}
}
JLabel AnswerKey2 = new JLabel(answerKey.toString());
return pos;
}
public HangmanPanel(final String s){
this.setLayout(null);
JLabel heading = new JLabel("Welcome to the Hangman App");
JButton Button = new JButton("Ok");
//get input
JLabel tfLable = new JLabel("Please Enter a Letter:");
final JLabel AnswerKey = new JLabel(dashReplace(answerKey()).toString());
final JTextField text = new JTextField(10);
heading.setSize(200, 50);
tfLable.setSize(150, 50);
text.setSize(50, 30);
Button.setSize(60, 20);
AnswerKey.setSize(200, 100);
heading.setLocation(300, 10);
tfLable.setLocation(50, 40);
text.setLocation(50, 80);
Button.setLocation(100, 85);
AnswerKey.setLocation(100,85);
this.add(heading);
this.add(tfLable);
this.add(text);
this.add(Button);
this.add(AnswerKey);
Button.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
// can't access text
String sc = text.getText();
char ch = sc.charAt(0);
findAndReplace(s, AnswerKey, sc, ch);
}
});
}
}
答案 0 :(得分:4)
为什么要尝试将setCharAt(...)与JLabel一起使用。标签用于显示静态文本。更改它的唯一方法是替换整个字符串。
我猜你可以这样做:
StringBuilder text = label.getText();
text.setCharAt(...);
label.setText( text.toString() );
另一种选择是使用看起来像JLabel的JTextField:
JTextField label = new JTextField(...);
label.setEditable(false);
label.setBorder(null);
label.setOpaque(false);
然后当您需要更改文本时:
label.select(...);
label.replaceSelection(...);
答案 1 :(得分:3)
可用于为JLabel
组件设置文本的唯一方法是setText
。 Strings
也是不可变的。因此,您可以使用StringBuilder
:
StringBuilder builder = new StringBuilder(answerKey.getText());
builder.setCharAt(pos, ch);
answerKey.setText(builder.toString());