Eclipse向我展示了这一行的多个标记:public void sendConnection(View view)
如果有人可以帮助我,非常感谢你
btr = (Button)findViewById(R.id.connection);
btr.setOnClickListener(new View.OnClickListener() {
public void onClick(View v)
{
EditText text = (EditText)findViewById(R.id.passwordedit);
String str = text.getText().toString();
if(str.equals("1234"))
{
public void sendConnection(View view)
{
Intent intent = new Intent(this, AddMasterNumber.class);
startActivity(intent);
}
}
else
{
AlertDialog alertdialog = new AlertDialog.Builder(MainActivity.this).create();
alertdialog.setTitle("Wrong Password");
alertdialog.setIcon(R.drawable.wrongpassword);
alertdialog.setMessage("The password you entered is incorrect, please try again!");
alertdialog.show();
}
}
});
答案 0 :(得分:3)
public void onClick(View v)
{
EditText text = (EditText)findViewById(R.id.passwordedit);
String str = text.getText().toString();
if(str.equals("1234"))
{
sendConnection(v);
}
else
{
AlertDialog alertdialog = new AlertDialog.Builder(MainActivity.this).create();
alertdialog.setTitle("Wrong Password");
alertdialog.setIcon(R.drawable.wrongpassword);
alertdialog.setMessage("The password you entered is incorrect, please try again!");
alertdialog.show();
}
}
public void sendConnection(View view)
{
Intent intent = new Intent(this, AddMasterNumber.class);
startActivity(intent);
}
你不能在另一个函数中声明一个函数;。