Question

我一直试图让这个工作过去几个小时了。我有cordova 2.2。

我创建了一个名为com.tester.newvideouri的新包。

我在这个包中有一个名为newVideoUri的类，其中包含以下内容

package com.tester.newvideouri;

import org.apache.cordova.api.CallbackContext;
import org.apache.cordova.api.CordovaPlugin;
import org.json.JSONArray;
import org.json.JSONException;

/**
 * This class echoes a string called from JavaScript.
 */
public class newVideoUri extends CordovaPlugin {
    @Override
    public boolean execute(String action, JSONArray args, CallbackContext callbackContext) throws JSONException {
        if (action.equals("echo")) {
            String message = args.getString(0); 
            this.echo(message, callbackContext);
            return true;
        }
        return false;
    }

    private void echo(String message, CallbackContext callbackContext) {
        System.out.println("success here and display it");
        if (message != null && message.length() > 0) { 
            callbackContext.success(message);
        } else {
            callbackContext.error("Expected one non-empty string argument.");
        }
    }
}

在我的config.xml我添加了以下行：

    <plugin name="Echo" value="com.tester.newvideouri.newVideoUri" />

在我的javascript文件中，我有以下内容：

    function onLoad() {
        document.addEventListener("deviceready", onDeviceReady, false);
    }
    window.onDeviceReady = function() {         
        window.echo = function(str, callback) {
            alert('Started');
            cordova.exec(callback, function(err) {
                callback('Nothing to echo.');
            }, "Echo", "echo", [ str ]);
            alert('The END');
        };          
        window.echo("echome", function(echoValue) {
            alert(echoValue == "echome"); // should alert true.
        });
    }

运行代码时没有任何反应。谁能告诉我我做错了什么？

Answer 1

将您的“echome”代码写入如下函数：

function echome(){
    window.echo("echome", function(echoValue){
    alert(echoValue == "echome");
    });
}

并在html代码中调用此函数，如下所示：

<a href="javascript:echome();">Click here</a>

尝试运行它。它对我有用。：）

Answer 2

根据此示例，代码是正确的：http://docs.phonegap.com/en/2.6.0/guide_plugin-development_android_index.md.html#Developing%20a%20Plugin%20on%20Android

可能你的问题是科尔多瓦未能“勾结”起来。你确实在你的网页上添加了cordova.android.js吗？

如果是这样，请确保实际调用设备：

window.onDeviceReady = function() {
  alert('ready to work'); 
   // if you do not see this alert nothing in cordova will work as 
   // it means communication was not started

}

Answer 3

您需要在javascript文件中输入：

cordova.define("cordova/plugin/sampleplugin", function(require, exports, module) {
  var exec = require('cordova/exec');
  var SamplePlugin = function() {};

  SamplePlugin.prototype.authenticate = function(loginId,plainTextPassword,successCallback,failureCallback) {
        return exec(successCallback, failureCallback, 'SamplePlugin', 'authenticate', [loginId,plainTextPassword]);

  }
        var sampleplugin = new SamplePlugin();
        module.exports = sampleplugin;
});

此处SamplePlugin是我插件的名称。

同样在你的html文件中，写下这段代码：

var sampleplugin = cordova.require("cordova/plugin/sampleplugin");
           function  callrestfulweb()
{
               var loginId= document.getElementById("loginId").value;
               var plainTextPassword = document.getElementById("plainTextPassword").value;
               sampleplugin.authenticate(loginId,plainTextPassword,function(){alert("login successful");},function(){alert("Invalid username or password ");})
       }

我希望你能通过这个例子理解。

Answer 4

您需要在javascript文件中输入：

cordova.define("cordova/plugin/sampleplugin", function(require, exports, module) {
  var exec = require('cordova/exec');
  var SamplePlugin = function() {};

  SamplePlugin.prototype.authenticate = function(loginId,plainTextPassword,successCallback,failureCallback) {
        return exec(successCallback, failureCallback, 'SamplePlugin', 'authenticate', [loginId,plainTextPassword]);

  }
        var sampleplugin = new SamplePlugin();
        module.exports = sampleplugin;
});

此处SamplePlugin是我的

的名称

同样在你的html文件中，写下这段代码

var sampleplugin = cordova.require("cordova/plugin/sampleplugin");
           function  callrestfulweb()
{
               var loginId= document.getElementById("loginId").value;
               var plainTextPassword = document.getElementById("plainTextPassword").value;
               sampleplugin.authenticate(loginId,plainTextPassword,function(){alert("login successful");},function(){alert("Invalid username or password ");})
       }

我希望你能通过这个例子理解。

Phonegap Cordova 2.2插件开发，无法在Java和JavaScript之间进行通信

4 个答案: