Question

对于我们使用Dropbox的全自动应用程序，我们需要使用'dropboxfs'（使用'pyfilesystem'的Dropbox FS层）自动登录Dropbox。构造函数预计

https://github.com/btimby/fs-dropbox/blob/master/dropboxfs.py#L336

来自oauth进程的令牌密钥+秘密。

我们能以某种方式自动化oauth流程吗？我没有任何手动交互，其中应用程序使用oauth窗口启动浏览器，并且我必须确认oauth访问请求。

app key + secret不是问题。但我只想为应用程序提供Dropbox用户名+密码，以便直接访问Dropbox。

任何选项？

Answer 1

我面临同样的挑战，我通过使用名为Splinter的Web应用程序的测试框架解决了这个问题。它允许我自动化浏览器操作。查看documentation页面。

这是我使用的代码：

from splinter import *
from dropbox import rest, session
from dropbox import client as dbclient
import time

# Initiate Dropbox API
APP_KEY = '###'
APP_SECRET = '###'
ACCESS_TYPE = 'dropbox'
sess = session.DropboxSession(APP_KEY, APP_SECRET, ACCESS_TYPE)
emailDropbox = '###'
passwordDropbox = '###'

request_token = sess.obtain_request_token()

urlDropbox = sess.build_authorize_url(request_token)

def phantomjsOAuth():
    # Target url
    print 'Target url: ', urlDropbox

    browser = Browser('phantomjs')
    print 'Starting phantomjs browser'
    print 'Visiting url'
    browser.visit(urlDropbox)

    # Email form
    print 'Is the email form present? ', browser.is_element_present_by_id('login_email')
    print 'Fill email form'
    browser.find_by_id('email-field').first.find_by_id('login_email').first.fill(emailDropbox)
    print 'Email form successfully filled'

    # Password form
    print 'Is the password form present? ', browser.is_element_present_by_id('login_password')
    print 'Fill password form'
    browser.find_by_id('login_password').first.fill(passwordDropbox)
    print 'Password form successfully filled'

    # Find login submit button
    print 'Is the "Submit" button present?', browser.is_element_present_by_name('login_submit_dummy')
    submitButton = browser.is_element_present_by_name('login_submit_dummy')

    if submitButton == True:
        print 'Pauzing for 5 seconds to avoid clicking errors'
        time.sleep(5)
        print 'Attempting to click the "Submit" button in order to login'
        browser.find_by_name('login_submit_dummy').first.click()
        print '"Submit" button successfully clicked'

        # Allow connection with Dropbox
        print 'Is the "Allow" button present?', browser.is_element_present_by_css('.freshbutton-blue')
        allowButton = browser.is_element_present_by_css('.freshbutton-blue')

        if allowButton == True:
            print 'The "Allow" button is present, attempting to click..'
            browser.find_by_css('.freshbutton-blue').click()
            print 'The "Allow" button is successfully clicked, access to Dropbox is granted.'

            dropboxCode()

        else:
            print 'The "Allow" button is not present, quitting.'
            browser.quit()

    else:
        print 'The "Submit" button was not present, quitting.'
        browser.quit()

def dropboxCode():
    # The rest of the Dropbox code
    # This will fail if the user didn't visit the above URL and hit 'Allow'
    access_token = sess.obtain_access_token(request_token)

    client = dbclient.DropboxClient(sess)
    print "linked account:", client.account_info()

    f = open('working-draft.txt')
    response = client.put_file('/magnum-opus.txt', f)
    print "uploaded:", response

phantomjsOAuth()

Answer 2

Dropbox API目前需要使用OAuth，这些条款禁止人们试图将其自动化的方式：

https://www.dropbox.com/terms#acceptable_use https://www.dropbox.com/developers/reference/bestpractice

（你真的不应该像那样存储你的用户名/密码。）

Answer 3

OAuth是Dropbox Core API提供的唯一身份验证，您无法使用用户名+密码来访问。

从Python自动执行Dropbox OAuth身份验证

3 个答案: