Question

我正在从主应用程序运行C＃服务器，我想将从服务器线程收到的消息传递给主线程。服务器应该在后台运行以进行新连接。每次有新连接时，服务器都应将收到的消息传递给主应用程序。如何让主应用知道何时收到消息？当有新连接时，如何将消息从服务器线程传递给main？

主要申请

  public partial class MainWindow : Window
 {
        TCPServer Server = new TCPServer(); //start running the server
        //get the message (Server.message) when a client sent it to the server
        //TODO process the message
    }

TCP服务器

class TCPServer
    {
        private TcpListener tcpListener;
        private Thread listenThread;
        private String message;

        public TCPServer()
    {
        this.tcpListener = new TcpListener(IPAddress.Any, 3200);
        this.listenThread = new Thread(new ThreadStart(ListenForClients));
        this.listenThread.Start();

    }

 //starts the tcp listener and accept connections
    private void ListenForClients()
    {
        this.tcpListener.Start();

        while (true)
        {
            //blocks until a client has connected to the server
            System.Diagnostics.Debug.WriteLine("Listening...");
            TcpClient client = this.tcpListener.AcceptTcpClient();
            System.Diagnostics.Debug.WriteLine("Client connected");


            //create a thread to handle communication 
            //with connected client
            Thread clientThread = new Thread(new ParameterizedThreadStart(HandleClientComm));
            clientThread.Start(client);
        }
    }


    //Read the data from the client
    private void HandleClientComm(object client)
    {

        TcpClient tcpClient = (TcpClient)client; //start the client
        NetworkStream clientStream = tcpClient.GetStream(); //get the stream of data for network access

        byte[] message = new byte[4096];
        int bytesRead;

        while (true) 
        {
            bytesRead = 0;

            try
            {
                //blocks until a client sends a message
                bytesRead = clientStream.Read(message, 0, 4096);
            }
            catch
            {
                //a socket error has occured
                break;
            }

            if (bytesRead == 0) //if we receive 0 bytes
            {
                //the client has disconnected from the server 


          break;
                }
                //message has successfully been received
                ASCIIEncoding encoder = new ASCIIEncoding();
                message = encoder.GetString(message, 0, bytesRead);

                //Reply
                byte[] buffer = encoder.GetBytes("ACK");
                clientStream.Write(buffer, 0, buffer.Length);
                System.Diagnostics.Debug.WriteLine("ACK");
                clientStream.Flush();
               }
            tcpClient.Close();
            System.Diagnostics.Debug.WriteLine("Client disconnected");
        }

Answer 1

TcpListener已经很好地支持了这一点，而是使用BeginAcceptTcpClient（）方法。当您从WPF或Winforms应用程序的主线程调用它时，回调将自动在同一主线程上运行。这同样适用于其BeginReceive（）方法。在内部，它使用调度程序循环来激活回调方法，非常类似于BackgroundWorker和C＃v5 async / await关键字这样的类的工作方式。

这使您免于开始终止自己的线程并确保正确编组的麻烦。并显着减少程序的资源使用。强烈推荐。

Answer 2

队列就是答案。特别是在这种情况下Concurrent Queue。

您的套接字线程将消息放入队列。您的工作线程轮询队列并拉出工作项。

对于基于套接字的应用程序，此模式非常非常常见。

或者，您可以针对系统线程池QueueUserWorkItem，让它管理工作负载。

注意：你现在处于多线程领域。您需要阅读有关同步和将要出现的其他问题。不这样做意味着你的应用程序会有非常奇怪的错误。

将数据从后台线程发送到主线程

2 个答案: