Question

我正在尝试发送一个调用webservice方法，该方法将锯齿状数组作为参数。我构建了数组，但它总是将null传递给Web服务。

这是我的java类：

package com.mitch.wcfwebserviceexample;

import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicHeader;
import org.apache.http.protocol.HTTP;
import org.json.JSONArray;
import org.json.JSONObject;

import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.TextView;
import android.app.Activity;

public class MainActivity extends Activity implements OnClickListener {
    private String values ="";
  Button btn;
  TextView tv;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        btn = (Button)this.findViewById(R.id.btnAccess);
        tv = (TextView)this.findViewById(R.id.tvAccess);
        btn.setOnClickListener(this);
    }

    @Override
    public void onClick(View arg0) {
        try
        {
        AsyncTaskExample task = new AsyncTaskExample(this);
        task.execute("");
        String  test = values;
        tv.setText(values);
        } catch(Exception e)
        {
           Log.e("Click Exception ", e.getMessage());   
        }

    }

    public class AsyncTaskExample extends AsyncTask<String, Void,String>
    {
        private String Result="";
        //private final static String SERVICE_URI = "http://10.0.2.2:1736";
        private final static String SERVICE_URI = "http://10.0.2.2:65031/SampleService.svc";
        private MainActivity host;
        public AsyncTaskExample(MainActivity host)
        {
            this.host = host;
        }

        public String GetSEssion(String URL)
        {
          boolean isValid = true;
          if(isValid)
          {

                    String[][] val = {
                        new String[] {"Student.ID","123456"},
                        new String[] {"Student.username","user1"},
                        new String[] {"Student.password","123456"},
                        new String[] {"Student.location.id","12"}
                    };
                    HttpPost requestAuth = new HttpPost(URL +"/Login");
                    try
                  {
                    JSONObject json = new JSONObject();
                //  json.put("sessionId", sessionId);
                    JSONArray params = new JSONArray();
                    params.put(val);
                    json.put("authenParams", params);

                    StringEntity se = new StringEntity(json.toString());
                    se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
                    requestAuth.setHeader("Accept","application/json");
                    requestAuth.setEntity(se);
                    DefaultHttpClient httpClientAuth = new DefaultHttpClient();
                    HttpResponse responseAuth = httpClientAuth.execute(requestAuth);
                    HttpEntity responseEntityAuth = responseAuth.getEntity();
                    char[] bufferAuth = new char[(int)responseEntityAuth.getContentLength()];
                    InputStream streamAuth = responseEntityAuth.getContent();
                    InputStreamReader readerAuth = new InputStreamReader(streamAuth);
                    readerAuth.read(bufferAuth);
                    streamAuth.close();
                    String rawAuthResult = new String(bufferAuth);
                    Result = rawAuthResult;
                    String d = null;
        //      }
            } catch (ClientProtocolException e) {
                Log.e("Client Protocol", e.getMessage());
            } catch (IOException e) {
                Log.e("Client Protocol", e.getMessage() );
            } catch(Exception e)
            {
                Log.e("Client Protocol", e.getMessage() );
            }
          }
          return Result;
        }

        @Override
        protected String doInBackground(String... arg0) {
            android.os.Debug.waitForDebugger();
            String t = GetSEssion(SERVICE_URI);
            return t;
        }

        @Override
        protected void onPostExecute(String result) {
        //  host.values = Result;
            super.onPostExecute(result);
        }
        @Override
        protected void onPreExecute() {
            // TODO Auto-generated method stub
            super.onPreExecute();
        }

        @Override
        protected void onCancelled() {
            // TODO Auto-generated method stub
            super.onCancelled();
        }
    }
}

下面是我应该接收参数的方法：我在下面的代码中加了一个断点并检查它。参数始终为null。

public string Login(string[][] value)
        {
            string[] tester = null;
            string testerExample="";
            foreach (string[] st in value)
            {
                tester = st;
            }

            foreach (string dt in tester)
            {
                testerExample = dt;
            }

            return testerExample;
        }

以下是IStudentService中的方法声明：

[OperationContract]
        [WebInvoke(
            Method="POST", UriTemplate="Login", BodyStyle= WebMessageBodyStyle.WrappedRequest, ResponseFormat = WebMessageFormat.Json, RequestFormat = WebMessageFormat.Json)]
        string Login(string[][] value);

我按照你的建议尝试了，但它没有用。它返回“请求错误” 以下是我粘贴的示例代码。

HttpClient client = new DefaultHttpClient();  
           HttpPost post = new HttpPost("http://10.0.2.2:65031/SampleService.svc/login");   
 List<NameValuePair> pairs = new ArrayList<NameValuePair>();  
pairs.add(new BasicNameValuePair("tester","abcd"));  
pairs.add(new BasicNameValuePair("sampletest","1234"));  
UrlEncodedFormEntity entity = new UrlEncodedFormEntity(pairs,HTTP.UTF_8);  
post.setEntity(entity);  
HttpResponse response = client.execute(post); 
HttpEntity responseEntity = response.getEntity();               
char[] buffer = new char[(int)responseEntity.getContentLength()];        
InputStream stream = responseEntity.getContent();        
InputStreamReader reader = new InputStreamReader(stream);        
reader.read(buffer);        stream.close();         
String value = new String(buffer);

Answer 1

我终于让它按照我想要的方式工作。问题是我以这种方式构建Array（参见下面的第1节）并将其传递给JSONObject或JSONArray。我使用JSONArray切换并构建了Array，并将其传递给JSONObject（参见第2节）。它就像一个魅力。

SECTION1：错误的方法 - （如果您要查看数组并将它们放在JSONArray中，它可能会以这种方式工作。当它可以直接完成时，这将是太多的工作。）
```
String[][] Array = {
new String[]{"Example", "Test"},
new String[]{"Example", "Test"},
};

JSONArray jar1 = new JSONArray();
jar1.put(0, Array); **// Did not work**
```

第2节：经过长时间的尝试后我的方式以及来自@vorrtex的一些非常有用的提示和提示。

JSONArray jar1 = new JSONArray();
jar1.put(0, "ABC");
jar1.put(1, "Son");
jar1.put(2, "Niece");

JSONArray jarr = new JSONArray();
jarr.put(0, jar1);

JSONArray j = new JSONArray();
j.put(0,"session");

JSONObject obj = new JSONObject();          
obj.put("value", jarr);
obj.put("test", j);
obj.put("name","myName");
Log.d("Obj.ToString message: ",obj.toString());
StringEntity entity = new StringEntity(obj.toString());

查看网络服务，它正是我所寻找的。

谢谢你的帮助!!!!

从Android发送.net Restful WebService的参数

1 个答案: