highInterestChecking标题:
#ifndef H_highInterestChecking
#define H_highInterestChecking
#include "noservicechargechecking.h"
#include <string>
class highInterestChecking: public noServiceChargeChecking
{
public:
highInterestChecking(std::string =" ",int = 0, double = 0.00, double = 0.00, double = 0.00);
};
#endif
highInterestChecking cpp:
#include "highInterestChecking.h"
using std::string;
highInterestChecking::highInterestChecking(string name, int acct, double bal, int numCheck, double min, double i)
{
bankAccount::setAcctOwnersName(name);
bankAccount::setAcctNum(acct);
bankAccount::setBalance(bal);
checkingAccount::setChecks(numCheck);
noServiceChargeChecking::setMinBalance(min);
noServiceChargeChecking::setInterestRate(i);
}
我有错误“没有重载功能的实例”。在cpp文件中的构造函数名称highInterestChecking下不确定是什么导致它我看了一会儿现在似乎找不到错误。也许有人会帮忙?
答案 0 :(得分:4)
在标题中你有:
highInterestChecking(std::string =" ",int = 0, double = 0.00, double = 0.00, double = 0.00);
哪个需要5
个参数,在源文件中:
highInterestChecking::highInterestChecking(string name, int acct, double bal, int numCheck, double min, double i)
^^^^^^^^^^^
取6
个参数。似乎int numCheck
与标题签名不匹配。
答案 1 :(得分:1)
你在类声明中有这个构造函数:
highInterestChecking(std::string =" ",int = 0, double = 0.00, double = 0.00, double = 0.00);
和类定义中的这个:
highInterestChecking::highInterestChecking(string name, int acct, double bal, int numCheck, double min, double i)
两个参数列表中的参数类型必须匹配。
答案 2 :(得分:1)
highInterestChecking::highInterestChecking(string name, int acct,
double bal, int numCheck, double min, double i)
//^^^
在你的类的头文件中不存在,头文件有5个参数,但你在cpp文件中有6个,参数类型似乎不匹配,